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WARRIOR [948]
3 years ago
14

The left and page numbers of an open book are two consecutive integers whose sum is 259 find the page numbers

Mathematics
1 answer:
Liula [17]3 years ago
7 0

Answer:

129 and 130

Step-by-step explanation:

Consecutive integers means 1,2,3,4,5... so on

That means we can model them as x,(x+1),(x+2)...

We are given the information that the sum of two consecutive integers is 259

so we can write

x + (x+1)=259

solving the above equation

x+x=259-1

2x=258

x=\frac{258}{2}

x=129

so the first page number of the book is 129 and the second is

x+1

129+1

130

Hence the page numbers are 129 and 130

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Which of the following is an example of a perfect square trinomial?
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Answer:

c

Step-by-step explanation:

A perfect square trinomial is always in the form

(a+b)(a+b)= a^{2} +2ab+b^2

ie. (x+4)(x+4)= x^{2} +8x+16

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2 years ago
When n is a factor of a number, all factors of n are also factors of the number
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This would be True. For example. If your number is 24, and 'n' is 12 ( a factor of 24 )
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3 years ago
Helppp will brainlist 20 points :((((
makvit [3.9K]

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Step-by-step explanation:

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2 years ago
A car moves at a speed that allows it to move 45 yards in 5⁄4 of a second. How long will it take a car at the same speed to move
Dimas [21]

First, to make things easier, let's turn 5/4 into a decimal given a second is equal to 1000 milliseconds.

5/4 = 1,25

1,25 * 1000 = 1250 milliseconds = 1.25 seconds


So, we've found that 45 yards can be covered in 1.25 seconds. Now we'll use the rule of 3:

45 - 1.25

80 - x


Now we solve:

(80 * 1.25) / 45 = x

100 / 45 = x

2,22... = x


So, according to our answer, 80 yards can be covered in 2,22 seconds, which in fractions would be:

2,22 =\frac{222}{100} = \frac{111}{50}


Hope it helped,


BioTeacher101

7 0
3 years ago
Read 2 more answers
A lidless box is to be made using 2m^2 of cardboard find the dimensions of the box that requires the least amount of cardboard
Jlenok [28]
1.8, Problem 37: A lidless cardboard box is to be made with a volume of 4 m3 . Find the dimensions of the box that requires the least amount of cardboard. Solution: If the dimensions of our box are x, y, and z, then we’re seeking to minimize A(x, y, z) = xy + 2xz + 2yz subject to the constraint that xyz = 4. Our first step is to make the first function a function of just 2 variables. From xyz = 4, we see z = 4/xy, and if we substitute this into A(x, y, z), we obtain a new function A(x, y) = xy + 8/y + 8/x. Since we’re optimizing something, we want to calculate the critical points, which occur when Ax = Ay = 0 or either Ax or Ay is undefined. If Ax or Ay is undefined, then x = 0 or y = 0, which means xyz = 4 can’t hold. So, we calculate when Ax = 0 = Ay. Ax = y − 8/x2 = 0 and Ay = x − 8/y2 = 0. From these, we obtain x 2y = 8 = xy2 . This forces x = y = 2, which forces z = 1. Calculating second derivatives and applying the second derivative test, we see that (x, y) = (2, 2) is a local minimum for A(x, y). To show it’s an absolute minimum, first notice that A(x, y) is defined for all choices of x and y that are positive (if x and y are arbitrarily large, you can still make z REALLY small so that xyz = 4 still). Therefore, the domain is NOT a closed and bounded region (it’s neither closed nor bounded), so you can’t apply the Extreme Value Theorem. However, you can salvage something: observe what happens to A(x, y) as x → 0, as y → 0, as x → ∞, and y → ∞. In each of these cases, at least one of the variables must go to ∞, meaning that A(x, y) goes to ∞. Thus, moving away from (2, 2) forces A(x, y) to increase, and so (2, 2) is an absolute minimum for A(x, y).
5 0
3 years ago
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