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sineoko [7]
3 years ago
14

The population of ticks in the forest and the temperature of the air have an indirect relationship. As the air temperature incre

ases, how does the population of ticks change?
Physics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

Based on this relationship scenario, as it is known that Ticks aren't capable of drinking water so they require a climate with high humidity to stay hydrated. A climate with high air temperature and low humidity is not ideal. At these condition, a tick can not comfortably survive and this is vice versa.

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consider the three vectors, A=3i+4j, B=2i-2j+4k, and C=-i+5j-3k. Show that the sum of the three vectors can alternatively be com
REY [17]

Answer:

A+B+C=7j+k

Explanation:

A=3i+4j

B=2i-2j+4k

C=i+5j-3k

A=3i+4j

+

B=<u>2</u><u>i</u><u>-</u><u>2</u><u>j</u><u>+</u><u>4</u><u>k</u>

i+2j+4k

A+B=i+2j+4k

+

C=<u>-i+</u><u>5</u><u>j</u><u>-</u><u>3</u><u>k</u>

7j+k

A+B+C=7j+k

4 0
2 years ago
A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

7 0
3 years ago
When a person's temperature reaches 104 degrees, the chances of survival are decreased dramatically. Group of answer choices Tru
Natali5045456 [20]

Answer:

True

Explanation:

With the increase in temperature hypothalamus fails and heatstroke occurs due to this failure. Hypothalamus is the region of our brain that act as a thermostat. It co-ordinates our physiological response to excessive heat. When the person’s temperature reaches to 104 degrees then it causes heatstroke. This heatstroke is very sudden and can kill person. Hence, we can conclude that when person’s temperature reaches to 104 degrees chances of survival decreases dramatically.

8 0
4 years ago
Determine the change in thermal energy of 100 g of copper (M = 63,5, Debye 348K) if it is cooled from
Setler [38]

Answer:

given,

mass of copper = 100 g

latent heat of liquid (He) = 2700 J/l

a) change in energy

Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (300 - 4)

Q = 11153.63 J

He required

Q = m L

11153.63 = m × 2700

m = 4.13 kg

b) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (78 - 4)

Q = 2788.41 J

He required

Q = m L

2788.41 = m × 2700

m = 1.033 kg

c) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (20 - 4)

Q = 602.90 J

He required

Q = m L

602.9 = m × 2700

m =0.23 kg

8 0
3 years ago
Find the pressure exerted by a 3000 N crate that has an area of 2m squared
ipn [44]
Pressure = Force/ Area = 3000/2 = 1500 pascal.
8 0
3 years ago
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