Dividing the first equation by 2
X + 2y = 12
Dividing the equation 2 by 4
-3x + 2y = -4
subtracting both equations
4x = 16
X = 4
Also 4 + 2y = 12
2y = 8
Y = 4
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The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
4
Step-by-step explanation:
5(x + 1) -x = 17 Distribute the 5
5x + 5 - x = 17 Combine like terms
4x + 5 = 17 Subtract 5 from both sides
4x = 12 Divide both sides by 4
x = 3
Three is the smaller integer and 4 is the greater integer.
F(x) = x + 8
This is because you are simply moving the y-intercept up 8 units.
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