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vichka [17]
4 years ago
13

A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th

e current. The rate of the current was 4 miles per hour. Find the rate of the rowing team in still water.
Mathematics
1 answer:
lys-0071 [83]4 years ago
4 0

Answer:   
 let x=rate of the rowing team in still water 
 x+4=rate of the rowing team with current 
 x-4=rate of the rowing team against current   
 travel time=distance/rate 
 .. 
 90%2F%28x%2B4%29=10%2F%28x-4%29 
 90x-360=10x+40 
 80x=400 
 x=5  rate of the rowing team in still water=5 mph

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Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
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x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






Download pdf
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3 years ago
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spayn [35]

Answer:

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Step-by-step explanation:

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