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Tju [1.3M]
3 years ago
8

Subtract -28-47-12 please help!

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:-87

Step-by-step explanation:

ivolga24 [154]3 years ago
4 0

Answer:

-87

Step-by-step explanation:

-28-47-12= -75-12=-87

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A candy store makes a 9-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $2.00 per pound, j
Musya8 [376]

Let

x--------> the amount of gummy candy in pounds

y--------> the amount of jelly beans in pounds

z-------->  the amount of hard candy in pounds

we know that

x+y+z=9 --------> equation 1

2x+3y+3z=23 --------> equation 2  

x=2y --------> equation 3  

Substitute equation 3 in equation 1 and equation 2

[2y]+y+z=9 -----> 3y+z=9 ------> equation 4

2[2y]+3y+3z=23 -----> 7y+3z=23 ------> equation 5  

using a graphing tool ------> Solve the system of equations

see the attached figure

the solution is the point (3,2)

z=3\ pounds\\y=2\ pounds

<u>Find the value of x</u>

x=2y

x=2*2=4\ pounds

therefore

<u>the answer is</u>

the amount of gummy candy is 4\ pounds

the amount of jelly beans is 2\ pounds

the amount of hard candy is 3\ pounds

8 0
3 years ago
Read 2 more answers
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
5 times the result of a number plus 7 equals 71 more than that number
lubasha [3.4K]
The answer is: 12.8
71 -7 = 64
64÷5=12.8
4 0
3 years ago
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Inessa [10]

Answer: 142°

Step-by-step explanation:

∡BAC= 38°

∡BAN= 180°-38° = 142°

7 0
2 years ago
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Find the sum of the squared residuals for each potential line of fit, and then determine which potential line is the true line o
Paul [167]

Answer:

.163

Step-by-step explanation:

not sure what so ever that is a hard question

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3 years ago
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