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KIM [24]
3 years ago
10

Mary’s dog weighs 185 pounds. Her dog needs to lose between 9 and 15 pounds. Between what two percentages, rounded to the neares

t whole numbers, should Mary’s dog lose weight with respect to its current weight of 185 pounds? Select your answers from the drop-down lists.
Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

talk to you're mother

Step-by-step explanation:

love you

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In order to check proportionality, we need to check it's divisibility for two instances, 
First = 35 - 30 /1 = 5/1 = 5
second = 30 - 25 / 2-1 = 5/1 = 5

As, slope (m), is constant for every step, the relation is proportional

Hope this helps!
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Among 200 students serveyed 70 are out of state 150 lives in queens and 50 out of state lives in queens find the probability tha
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Total is 170 so <span><span>170/200</span></span>
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3 years ago
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Which matrix translates the vector 〈4,-3〉 to 〈6,-8〉?
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3 0
3 years ago
Mr. James McWhinney, president of Daniel-James Financial Services, believes there is a relationship between the number of client
vlada-n [284]

Answer:

\sum_{i=1}^n x_i = 334

\sum_{i=1}^n y_i =611

\sum_{i=1}^n x^2_i =13970

\sum_{i=1}^n y^2_i =51581

\sum_{i=1}^n x_i y_i =26584

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=13970-\frac{334^2}{10}=2814.4

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=26584-\frac{334*611}{10}=6176.6

And the slope would be:

m=\frac{6176.6}{2814.4}=2.195

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{334}{10}=33.4

\bar y= \frac{\sum y_i}{n}=\frac{611}{10}=61.1

And we can find the intercept using this:

b=\bar y -m \bar x=61.1-(2.195*33.4)=-12.213

So the line would be given by:

y=2.195 x -12.213

Step-by-step explanation:

The data given on this case is:

x: 14,12,20,16,46,23,48,50,55,50

y: 24,24,28,30,80,30,90,85,120,110

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 334

\sum_{i=1}^n y_i =611

\sum_{i=1}^n x^2_i =13970

\sum_{i=1}^n y^2_i =51581

\sum_{i=1}^n x_i y_i =26584

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=13970-\frac{334^2}{10}=2814.4

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=26584-\frac{334*611}{10}=6176.6

And the slope would be:

m=\frac{6176.6}{2814.4}=2.195

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{334}{10}=33.4

\bar y= \frac{\sum y_i}{n}=\frac{611}{10}=61.1

And we can find the intercept using this:

b=\bar y -m \bar x=61.1-(2.195*33.4)=-12.213

So the line would be given by:

y=2.195 x -12.213

5 0
3 years ago
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