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Alexxx [7]
3 years ago
11

How do I solve this?

Mathematics
1 answer:
GuDViN [60]3 years ago
4 0
\bf \sqrt{xy}\sqrt{x^3y^5}\implies \sqrt{xy\cdot x^3y^5}\implies \sqrt{x^1x^3y^1y^5}\implies \sqrt{x^{1+3}y^{1+5}}
\\\\\\
\sqrt{x^4y^6}\implies \sqrt{(x^2)^2(y^3)^2}\implies x^2y^3
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If you could help I would really appreciate it, but if not that’s fine. Thank you.
Kobotan [32]
Since 7 is greater than 5, you input it into the last equation.

2•(7) -7
14-7
7

The answer is 7!
3 0
2 years ago
Need help also if you can can you do it step-by-step explanation please thank you 3(c + 8) = 28<br>​
skelet666 [1.2K]

Answer:

c = 4/3

Step-by-step explanation:

3(c + 8) = 28

Since we have paranthesis, first use the dsitributive property [multiply 3 by c and 8]

3(c + 8) = 28

3c + 24 = 28

To find the value of c, you must have c alone on one side, so subtract 24 from both sides

3c + 24 = 28

3c = 4

Now, divide by 3 to both sides to get your answer

3c = 4

c = 4/3

Therefore, the answer is 4/3!

I hope this helps! :)

3 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP???!!!!!! !!!!
storchak [24]

Answer:

your answer is C

Step-by-step explanation:


7 0
3 years ago
Suppose a bag contains 7 blue chips ad 3 gold chips.What is the probability of randomly choosing a gold chip,not replacing it,an
castortr0y [4]

|\Omega|=10\cdot9=90\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{90}=\dfrac{1}{15}\approx7\%

6 0
3 years ago
Suppose there are 8 boys and 7 girls in a classroom. If one student is chosen at random to run a errand. What is the probability
LUCKY_DIMON [66]

Answer:

47%

Step-by-step explanation:

There are 15 total students, so find the percentage of girls out of the total students: 7/15= .466, which is about 47%. To double check, you can do the boys and make sure it adds to 100%. 8/15= .533, which is about 53%. 47+53=100. So girls are 47% and boys are 53%

4 0
2 years ago
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