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3241004551 [841]
2 years ago
5

PLEASE HELP. I have no idea what to do

Mathematics
2 answers:
Mariulka [41]2 years ago
4 0

Answer:

What is it i can probably help

Step-by-step explanation:

Mademuasel [1]2 years ago
3 0

since \to :  x \sqrt[y]{ {n}^{z} }  = x( {n}^{ \frac{z}{y} } ) \\ then \: lets \: solve \: both \: values \: separately \to :  \\ \underline{ \boxed{solution \: to \:  \boxed{a}}} \\  120 \sqrt[3]{ {n}^{a} }  = 3 \sqrt{n} (40 \sqrt[6]{n} ) \\ 120 \sqrt[3]{ {n}^{a} }  = 3 \sqrt{n}  \times 40 \sqrt[6]{n} \\ 120 \sqrt[3]{ {n}^{a} }  = 120 (\sqrt{n} \times \sqrt[6]{n} ) \\ \sqrt[3]{ {n}^{a} }  = (\sqrt{n} \times \sqrt[6]{n} ) \\  {n}^{ \frac{a}{3} }  = {n}^{ \frac{1}{2} } \times {n}^{ \frac{1}{6} } \\ \frac{a}{3}  =  \frac{1}{2}   +   \frac{1}{6}  \\  \frac{a}{3}  =  \frac{4}{6}  \\ 6a = 12 \\ a =  \frac{12}{6}  =  2 \\ \underline{ \boxed{a  = 2 \:}}  \\  \\ \: \underline{ \boxed{solution \: to \:  \boxed{b}}} \\  27 \sqrt[4]{ {n}^{b} }  = 3 \sqrt{n} (9 \sqrt[4]{n} ) \\ 27 \sqrt[4]{ {n}^{b} }   = 3 \sqrt{n}  \times 9 \sqrt[4]{n} \\ 27 \sqrt[4]{ {n}^{b} }  = 27 (\sqrt{n} \times \sqrt[4]{n} ) \\ \sqrt[4]{ {n}^{b} }  = (\sqrt{n} \times \sqrt[4]{n} ) \\  {n}^{ \frac{b}{4} }  = {n}^{ \frac{1}{2} } \times {n}^{ \frac{1}{4} } \\ \frac{b}{4}  =  \frac{1}{2}   +   \frac{1}{4}  \\  \frac{b}{4}  =  \frac{3}{4}  \\ 4b = 12 \\ b =  \frac{12}{4}  =  3 \\ \underline{ \boxed{b  = 3 \:}}  \\ hence \to :  \\  \underline{ \underline{\boxed{a  = 2 \:}} \underline{ \boxed{b  = 3 \:}}}

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