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galben [10]
2 years ago
12

5 pounds of rice at a store cost $6.50 use the ray tool to graph the cost C, vs pounds of rice

Mathematics
1 answer:
Kobotan [32]2 years ago
4 0

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pounds of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for number of pounds (P) and cost (C) the we can graph the points from that table to get the final graph.

Attached graph is the final graph.

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A minor league baseball team plays 101 games in a season. If the team won 14 more than twice as many games as they lost, how man
vagabundo [1.1K]
A minor league plays 101 games,
They win 14 more than twice as many as they lost.
How many wins and loses?

Okay, simple.
First, write a simple addition equation. In this case wins = w and losses = l.
l + w = 101.

Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
l = l
w = 2l +14 (14 more than twice the amount)

Okay. So plug in the new amount for w.
l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
put similar terms together.
3l + 14 = 101
3l = 87
l = 29
So, we have 29 loses, and
w = 2(29) + 14
72 wins!
To check,
72 + 29 = 101, correct!

Hope this helps!

7 0
3 years ago
A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor
Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 700, \sigma = 50.

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

Z = \frac{X - \mu}{\sigma}

Z = \frac{790 - 700}{50}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

Z = \frac{X - \mu}{\sigma}

Z = \frac{575 - 700}{50}

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
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