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3 years ago

I need help a problem 11

Mathematics

2 answers:

Dimas [21]3 years ago

5 0

Answer:

x=5

Step-by-step explanation:

vovangra [49]3 years ago

5 0

Answer:

x = 68

Step-by-step explanation:

The formula for calculating the sum of interior angles of a polygon is: (n - 2) x 180° (where n is the number of sides)

This polygon has 5 sides, so the sum of the interior angles:

(5 - 2) x 180° = 540°

To find x, add together all the angle expressions, equate to 540 and solve for x:

U + V + W + Y + Z = 540

(x - 8) + (3x - 11) + (x + 8) + x + (2x + 7) = 540

Gather like terms: x + 3x + x + x + 2x - 8 - 11 + 8 + 7 = 540

Combine like terms: 8x -4 = 540

Add 4 to both sides: 8x = 544

Divide both sides by 8: x = 68

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What is the Y 2(7y−1)=40

MissTica

Answer:

Step-by-step explanation:

2(7y−1)=40

14y-2=40

14y=40+2

14y=42

y=3

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5 0

3 years ago

Read 2 more answers

Help giving brainly if correct show work to get full points

prohojiy [21]

Answer:

Step-by-step explanation:

This is an geometric series.

Common ratio = second number÷ first number

$= \dfrac{4096}{-1024} = -4$

To get the next number, 256 should be divide by (-4)

$\dfrac{256}{(-4)}= -64 \\\\\\\dfrac{-64}{-4}=16\\\\\\\dfrac{16}{-4}=-4$

The three numbers are : -64 , 16 , -4

6 0

2 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

What is the answer to 36÷9 using a number line?

Katarina [22]

To divide 36/9 using the number line you have to jump from zero with length of 9 until reach 36, and the result will be the number of jumps.

I do the jumps by steps, but you can draw in the number line:

0. First jump from 0 to 9.

1. Second jump from 9 to 9+9=18.

2. Third jump from 18 to 18+9=27.

3. Fourth jump from 27 to 27+9=36.

4. Great!! We already reach 36.

So, we need four jumps of 9 to reach 36 from 0.

So, the result is 36/9=4

4 0

1 year ago

Please answer all please

Firdavs [7]

Answer:

Step-by-step explanation:

The first parabola has vertex (-1, 0) and y-intercept (0, 1).

We plug these values into the given vertex form equation of a parabola:

y - k = a(x - h)^2 becomes

y - 0 = a(x + 1)^2

Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

1 = a(0 + 1)^2, and from this we know that a = 1. Thus, the equation of the first parabola is

y = (x + 1)^2

Second parabola: We follow essentially the same approach. Identify the vertex and the two horizontal intercepts. They are:

vertex: (1, 4)

x-intercepts: (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

0 - 4 = a(3 - 1)^2, or

-4 = a(2)². This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

7 0

3 years ago