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GREYUIT [131]
3 years ago
7

On the basis of bonding, which of the following is true about potassium chloride when compared to sucrose?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0
Ionic bonding is present for potassium chloride. Two opposite ions attract and for a bond called the ionic bond. On the other, sucrose has a covalent bonding where electrons are shared between atoms.  Between this two bonds, ionic is the much stronger  bond therefore the correct answer is the first option. Potassium chloride has a higher boiling point than sucrose.
ELEN [110]3 years ago
5 0

Answer: Potassium chloride dissolves in water, but sucrose does not

Step-by-step explanation:

Potassium chloride is an ionic compound whereas sucrose is a covalent compound. And ionic compounds being polar ,easily dissolve in polar solvents such as water whereas covalent compounds being non polar dissolve only in nonpolar solvents.

Ionic compounds are held together by strong electrostatic forces and thus have high melting and boiling points. Ionic compounds are arranged in crystal lattice and are hard.


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Analyze the diagram below and complete the instructions that follow.<br> Find the value of x.
LUCKY_DIMON [66]

Answer:

10

Step-by-step explanation:

since it is a right angle triangle

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3 0
3 years ago
Given this figure on a coordinate plane, determine which of the following statements
hammer [34]
Answer is D. Show that AC and BC bisect each other and meet at the same point
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3 years ago
How do you do this I’m in 9th grade
pashok25 [27]

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Step-by-step explanation:

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8 0
3 years ago
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HACTEHA [7]

Answer:

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Step-by-step explanation:

<em>Volume</em><em> of</em><em> a</em><em> cylinder</em><em> </em><em>=</em><em> </em><em>πr²</em><em>h</em>

<em>Given</em>

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<em>r </em><em>=</em><em> </em><em>5</em><em>c</em><em>m</em>

<em>h </em><em>=</em><em> </em><em>1</em><em>4</em><em>c</em><em>m</em>

<em>Substitute</em><em> the</em><em> </em><em>given</em><em> </em><em>information</em><em> </em><em>in</em><em> the</em><em> </em><em>problem</em><em>.</em>

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4 0
2 years ago
Pls I need help thank you
Ket [755]

Answer:

3rd one

hope this will help you

7 0
3 years ago
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