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kolbaska11 [484]
4 years ago
11

PLEASE HELP Find F(3)-g(2)

Mathematics
1 answer:
marysya [2.9K]4 years ago
7 0

Answer:

-6

Step-by-step explanation:

for f(x), x=3, which is greater than 2, choose the second function.

so, f(3)=| 3-4 | = | -1 | = 1

for g(x), x=2, which is greater than 1, choose the second function.

so, g(2)= 3*2+1 = 7

f(3)-g(2)= 1-7=-6

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Which of the following polynomial functions is graphed below? OA. f(x) = (x - 2) ^ 2 * (x + 3) * (x - 1) O B. f(x) = (x + 2) ^ 2
laila [671]

The function of the polynomial is (b) f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)

From the graph, we have the following highlights

  • The graph crosses the x-axis at x = -1 and x = 3
  • The graph touches the x-axis at x = -2

The above highlights mean that:

  • The function has a multiplicity of 1 at x = -1 and x = 3
  • The function has a multiplicity of 2 at x = -2

So, the function of the polynomial is:

f(x) =a(x + 2)^2(x + 1)(x - 3)

Assume a = 1.

So, we have:

f(x) =1(x + 2)^2(x + 1)(x - 3)

Multiply

f(x) =(x + 2)^2(x + 1)(x - 3)

Hence, the function of the polynomial is (b) f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)

Read more about polynomial graphs at:

brainly.com/question/8878887

8 0
3 years ago
Greg bought a new car for £18000.
Whitepunk [10]

Answer:

£9318.96

Step-by-step explanation:

18000×0.7×0.86^(2)=£9318.96

3 0
3 years ago
What is a conversion factor that you can use to covert gallons to pints
____ [38]
Do a gallon man 1G 4Q 2P 2C
7 0
3 years ago
Help please thanks so much
suter [353]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help, please, I'm willing to give 24 points!
Margaret [11]
(1) 2 of one step equations

x - 23 = 8
x - 23 + 23 = 8 + 23
x = 31

n + 2 = 9
n + 2 - 2 = 9 - 2
n = 7

(2) 2 equations with fractions

3/4 (x + 3) = 9
4 [ 3/4 (x + 3) ] = 4[9]
3 (x + 3) = 36
3x + 9 - 9 = 36 - 9
3x/3 = 27/3

1/3 x 3/4
cross multiply
so 3/12 and simplify which makes it
1/4

(3) distributive property

3(2 + 4) = (3 • 2) + (3 • 4)
3(6) = 6 + 12
18 = 18


4 0
3 years ago
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