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3 years ago

A quantity with an initial value of 850 grows continuously at a rate of 90% per

Mathematics

1 answer:

vredina [299]3 years ago

7 0

Answer:

5400

Step-by-step explanation:

so 90% of 850 is 765 (0.90x850)

765 is 10 years

so 1 year is 765/10 = 76.5 per year. So 76.5x59 = 4,513.5 add the initial ammount and you got 5,363.5 in the nearest hundredth you get 5400

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How do you solve y=5/8b + 10 for b

joja [24]

Answer:

b = $\frac{8y-80}{5}$

Step-by-step explanation:

Given

y = $\frac{5}{8}$ b + 10

Multiply through by 8 to clear the fraction

8y = 5b + 80 ( subtract 80 from both sides )

8y - 80 = 5b ( divide both sides by 5 )

$\frac{8y-80}{5}$ = b

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4 years ago

What is 48/400 as a decimal??

kkurt [141]

Answer: 0.12

Step-by-step explanation:

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A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.

KIM [24]

9514 1404 393

Answer:

absolute error: 0.4 kg
relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

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3 years ago

What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

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3 years ago