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Ede4ka [16]
3 years ago
5

Simplify 3(x-4)+8(x+2) A) 11x-4 B)11x+4 C)11x-2

Mathematics
1 answer:
swat323 years ago
7 0
It is depending upon multiplication of values to variable and values of numbers again. Here the answer is Option B) 11x + 4. Here is my process on this equating expression.

For this we have to apply the law of distribution or the distributive law, in this we distribute the parentheses into the brackets to further expand them, we further eliminate the bracketed groups and perform the calculations. So, it is stating that, for any number, variable or a quantity if multiplied into a bracketed expression yields two products of multiplication of two quantities; one being the first quantity outside the brackets and two separately distinguished quantities inside the brackets. They are furthermore subtracted by the first quantity to that of the second quantity to obtain and achieve the distributive law.

If I were to express it through mathematical LaTeX Expressions, it will be represented as the first quantity as a variable of "a" where it can exhibit a value or a variable or a term or rule, etc. and then inside the brackets represented as "b" and "c".

Performing the law of distribution of values, variables, etc. It is demonstrated as:

\boxed{\mathbf{a \times (b - c) = a \times b - a \times c}}

We are given the values of the variables as a separate context and addition of two expressions. So, for both of them:

\mathbf{First \: \: Expression: \: 3 (x - 4)}

\mathbf{Second \: \: Expression: \: 8 (x + 2)}

Apply the following distribution law to expand the values onto variables and numbered values inside the brackets.

So, the variable "a", "b" and "c"; For First Expression is: a = 3, b = x and c = 4.

And, Similarly, for the variable of "a", "b" and "c", For Second Expression is: a = 8, b = x and c = 2.

Therefore, According to our distributive law of expanding the components will directly yield us:

\mathbf{3 \times x - 3 \times 4 + 8 \times x + 8 \times 2}

\mathbf{3x - 12 + 8x + 16}

Regroup the terms for a better visualisation and a clearer understanding for similarities between the terms; it makes it more easier to proceed further. So:

\mathbf{3x + 8x - 12 + 16}

All we did, was to separate the variable attached numbered values and shift it on one side; And, separating or shifting the values without variables to the other side.

\mathbf{11x - 12 + 16}

\boxed{\huge{\mathbf{Required \: \: Answer: \: 11x + 4}}}

Hope it helps.
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In a sewage treatment plant, a large concrete tank initially contains 440,000 liters of liquid and 10,000 kg of fine suspended s
viva [34]

Answer:

Concentration = 8.26kg/m^3

Step-by-step explanation:

Given

  V = 440000L --- volume of tank

m = 10,000 kg --- solid mass

r = 40000L/hr --- outflow rate  

Required

Determine the concentration at the end of 4 hours

First, calculate the amount of liquid that has been replaced at the end of the 4 hours.

Amount = r * Time

Amount = 40000L/hr * 4hr

Amount = 40000L * 4

Amount = 160000L

This implies that, over the 4 hours; The tank has 160000 liters of liquid out of 440000 liters were replaced

Calculate the ratio of the liquid replaced.

Ratio = \frac{Amount}{Volume}

Ratio = \frac{160000L}{440000L}

Ratio = \frac{16}{44}

Ratio = \frac{4}{11}

Next, calculate the amount of solid left.

Amount (Solid)= Ratio * m

Amount (Solid)= \frac{4}{11} * 10000kg

Amount (Solid)= \frac{40000}{11}kg

Amount (Solid)= 3636kg

Lastly, the concentration is calculated as:

Concentration = \frac{Amount (Solid)}{Volume}

Concentration = \frac{3636kg}{440000L}

Convert L to cubic meters

Concentration = \frac{3636kg}{440000* 0.001m^3}

Concentration = \frac{3636kg}{440m^3}

Concentration = 8.26kg/m^3

3 0
3 years ago
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