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iogann1982 [59]
3 years ago
6

Help me plz help help help

Physics
1 answer:
lianna [129]3 years ago
7 0
You can do experience pain in many ways. Some mental pain is loss of a loved one, or loss of a pet. Some physical pain is falling and skinning your knee, or breaking a bone. Please mark me brainliest! :)
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solong [7]
The rotation of Earth is equivalent to one day which is comprised of 24 hours. To determine the number of miles in Earth's circumference, one simply have to multiply the given rate by the appropriate conversion factor and dimensional analysis. This is shown below.
 
                  C = (1038 mi/h)(24 h/1 day)
                   C = 24,912 miles

From the given choices, the nearest value would have to be 20,000 mile. The answer is the second choice. 
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3 years ago
what is the largest and smallest possible resultant force of two force with magnitude of 41N and 14N​
MArishka [77]

Explanation:

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3 years ago
Hey, I need help can someone help me out, please?
yan [13]

Explanation:

6) newton

7) f =ma = 15*15 = 225N

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3 years ago
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What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
Dimas [21]

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s

So, the correct option is (B).

8 0
3 years ago
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Sometimes, when the wind blows across a long wire, a low-frequency "moaning" sound is produced. The sound arises because a stand
Crazy boy [7]

Answer:

The smallest integer is n = 4

Explanation:

Using the equation V= Sqrt(F/Linear density)

V= Sqrt(341/0.0120)

V= Sqrt(28416.7)

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Path distance =[ (n +1)/2]lambda

But V= f(Lambda)

n lambda/2 =L

n = f2L/V

n = (20 × 2 × 16.86) / 168.57

n = 4.0007

The smallest integer is n= 4

6 0
3 years ago
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