Electrical energy hope this helps <3
Answer:
138.18 minutes
Explanation:
= Latent heat of water at 0°C = 80 cal/g
m = Mass of water = 570 g
Heat removed for freezing
Let N be the number of cycles and each cycle removes 56 cal from the freezer.
So,
Each cycle takes 10 seconds so the total time would be
The total time taken to freeze 138.18 minutes
Answer:
120 kg•m/s.
Explanation:
From the question given above, the following data were obtained:
Case 1
Mass of object = M
Velocity of object = V
Momentum = 15 kg•m/s
Case 2
Mass of object = 2M
Velocity of object = 4V
Momentum = ?
Momentum is defined as follow:
Momentum = mass × velocity
The momentum of object in case 2 can be obtained as follow:
From case 1
Momentum = mass × velocity
15 = M × V
15 = MV ....... (1)
From case 2:
Momentum = mass × velocity
Momentum = 2M × 4V
Momentum = 8MV ....... (2)
Finally , substitute the value of MV in equation 1 into equation 2.
Momentum = 8MV
MV = 15
Momentum = 8 × 15
Momentum = 120 kg•m/s
Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s
The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
where
is the car's speed
is the duration of the car ride
Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
which becomes
(1)
we also know that the train speed is 5 km/h greater than the car's speed:
(2)
If we put (2) into (1), we find
and if we solve it, we find
So, the car speed is 20 km/h and the train speed is 25 km/h.
Answer:
The force of friction acting on block B is approximately 26.7N. Note: this result does not match any value from your multiple choice list. Please see comment at the end of this answer.
Explanation:
The acting force F=75N pushes block A into acceleration to the left. Through a kinetic friction force, block B also accelerates to the left, however, the maximum of the friction force (which is unknown) makes block B accelerate by 0.5 m/s^2 slower than the block A, hence appearing it to accelerate with 0.5 m/s^2 to the right relative to the block A.
To solve this problem, start with setting up the net force equations for both block A and B:
where forces acting to the left are positive and those acting to the right are negative. The friction force F_fr in the first equation is due to A acting on B and in the second equation due to B acting on A. They are opposite in direction but have the same magnitude (Newton's third law). We also know that B accelerates 0.5 slower than A:
Now we can solve the system of 3 equations for a_A, a_B and finally for F_fr:
The force of friction acting on block B is approximately 26.7N.
This answer has been verified by multiple people and is correct for the provided values in your question. I recommend double-checking the text of your question for any typos and letting us know in the comments section.