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evablogger [386]

3 years ago

10

Only the circled ones

1 answer:

ozzi3 years ago

5 0

2.

M must be (0,0) since it coincides with the origin
R must be (a+b, √(a²-b²)).
The x-coordinate is b from A translated to the right by a.
The y-coordinate is the same as A.

(I think the square root is there to confuse you).

3.

R(0,0)
C(a,b) (same x as T, same Y as E)

5.

Not sure how to prove that.

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Answer the questions.

Paladinen [302]

Answer:

5.

Objective C

$125x + 200 \geqslant 1200 \\ 125x \geqslant 1000 \\ x \geqslant 8$

7

$x \: \alpha \: y \\ y = kx \\ 2.00 = k \times 8 \\ k = \frac{2.00}{8} \\ k = 0.25$

3 0

2 years ago

the velocity of a motorcycle increases by acceleration of 2ms-2 and comes 20ms -1 in 5 seconds find the initial velocity of the

KonstantinChe [14]

a = v-u/t

2 = 20 - u / 5

10= 20-u

u = 10 m/s

7 0

2 years ago

Banking fees have received much attention during the recent economic recession as banks look for ways to recover from the crisis

alex41 [277]

Answer:

a) The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79

b) $0.57

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{1.86}{\sqrt{41}} = 0.57$

So the answer for b) is $0.57.

The lower end of the interval is the sample mean subtracted by M. So it is 12.22 - 0.57 = $11.65

The upper end of the interval is the sample mean added to M. So it is 12.22 + 0.57 = $12.79

The 95% confidence interval to estimate the average fee for the population is between $11.65 and $12.79

6 0

3 years ago

A + 4 = 6, when a = 2. true false open

stealth61 [152]

True
Pls mark brainliest

4 0

3 years ago

Read 2 more answers

Given: F(x) = 3x^2+1, G(x) = 2x - 3, H(X) = x<br> Find F(x) + G(x) =

weqwewe [10]

$F(x)+G(x)=3x^2+2x-2.$

Solution:

Given data: $F(x)=3x^2+1$ and $G(x)=2x-3$

To find F(x) + G(x):

Adding two functions which gives another function.

Substitute F(x) and G(x), we get

$F(x)+G(x)=(3x^2+1)+(2x-3)$

$=3x^2+1+2x-3$

$=3x^2+2x-3+1$

$=3x^2+2x-2$

$F(x)+G(x)=3x^2+2x-2$

Hence, $F(x)+G(x)=3x^2+2x-2.$

4 0

2 years ago