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3 years ago

Only the circled ones

Mathematics

1 answer:

ozzi3 years ago

5 0

2.

M must be (0,0) since it coincides with the origin
R must be (a+b, √(a²-b²)).
The x-coordinate is b from A translated to the right by a.
The y-coordinate is the same as A.

(I think the square root is there to confuse you).

3.

R(0,0)
C(a,b) (same x as T, same Y as E)

5.

Not sure how to prove that.

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Jobisdone [24]

Answer:

n 1932 DeBakey devised the “roller pump,” an essential component of the heart-lung machine that permitted open-heart surgery. He also developed an efficient method of correcting aortic aneurysms by grafting frozen blood vessels to replace diseased vessels.

Works written: The New Living Heart

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Step-by-step explanation:

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2 years ago

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Order of fractions from least to greatest 5/8,3/4,1/2,9/16

rusak2 [61]

Answer:

1/2, 9/16, 5/8, 3/4

Step-by-step explanation:

3 0

3 years ago

i used the answer key to get my answer and checked it with my dumb useless teacher and it’s right but, he won’t tell me how to g

gizmo_the_mogwai [7]

You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)

7 0

3 years ago

When she adds 2 to both sides, the equation 4x = 3x results. Which solution will best illustrate what happens to x ?

Natasha2012 [34]

Step-by-step explanation:

4x=3x

2+4x=3x+2

4x-3x=2-2

1x=0

x=1/0

X=0

(i think the question given was incomplete but this waht i could do with the given statement)

4 0

2 years ago

Read 2 more answers

I have some cheese. I used

hram777 [196]

<h3>Answer: 2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0

3 years ago