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Blababa [14]
3 years ago
5

A 30.0 mL sample of phosphoric acid is neutralized with 18.0 mL of a 3.00 M NaOH solution in a titration.

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer: The Answer is 0.3.

Explanation: Solved in the attached picture.

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Where more of hydrogen are contained in 90 g of water or in 80 g of methane
Lynna [10]
Methane.

Water - H2O
Methane - CH4

Methane has 2 more hydrogens than water.
7 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point (in °C) of a solution with 83.6 g of AgNO 3 in 1.00 k
Thepotemich [5.8K]

Answer:

  • <u>Freezing point: - 1.83ºC</u>
  • <u>Boiling point: 100.50ºC</u>

Explanation:

The <em>freezing point</em> and<em> boiling point</em> of solvents, when a solute is added, will change accordingly to the concentration of the solute particles.

The freezing point will decrease and the boiling point will increase. These are two colligative properties.

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3 years ago
Research and describe one career in health and fitness that you would consider
kiruha [24]
I would research the job of being a fitness coach, that is very popular in health and fitness
6 0
3 years ago
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Draw the product(s) that are expected when tert-butyl bromide undergoes solvolysis in isopropanol, (CH3)2CHOH.
N76 [4]
Those reactions in which Alkyl Halide reacts with the solvent without the involvement of any acid or base is called as Solvolysis. In given problem <em>tert</em>-Butyl Bromide is a tertiary Alkyl Halide and we know well that tertiary alkyl halides undergo SN¹ and E¹ elimination reaction due to the formation of stable tertiary carbocation. In given example after the formation of carbocation when Isopropyl act as nucleophile it will produce ether and when it acts as a base it will produce unsaturated compound. The reaction along with both products is shown below,

5 0
3 years ago
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I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
valentina_108 [34]

Answer:

C. NaHCO3 → Na2CO3 + H2O + CO2

Explanation:

» For a balanced equation, the number of atoms of reactants and products must be equal.

» In equation C, the reactant side has one sodium atom while ptoduct side has 2 sodium atoms.

» The balanced equations mus be;

{ \rm{ 2NaHCO _{3(aq)} → Na _{2}CO _{3(s)}+ H _{2} O _{(l)} + }CO _{2(g)} }

7 0
2 years ago
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