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3 years ago

A 30.0 mL sample of phosphoric acid is neutralized with 18.0 mL of a 3.00 M NaOH solution in a titration.

Chemistry

1 answer:

Morgarella [4.7K]3 years ago

8 0

Answer: The Answer is 0.3.

Explanation: Solved in the attached picture.

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Why is the sky black in space

Shkiper50 [21]

Answer:Since there is virtually nothing in space to scatter or re-radiate the light to our eye, we see no part of the light and the sky appears to be black.

Explanation:

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2 years ago

What are some of the positive and<br> negative effects of the use of plastics?

trapecia [35]

Answer:

Positive: Save fuel and reduces greenhouse gas

Negative: Harmful to human and animal health ( underwater animals), Hurts the food chain

Explanation:

I got it from a video. Hopefully it helps you.

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3 years ago

g All of the molecules below have polar bonds but only one of the molecules is a polar molecule. Which one is a polar molecule?

lbvjy [14]

Answer: $NF_3$

Explanation:

Geometrical symmetry of the molecule and the polarity of the bonds determine the polarity of the molecule.

The molecule that has zero dipole moment that means it is a geometrically symmetric molecule and the molecule which has some net dipole moment means it is a geometrically asymmetric molecule.

As the molecule is symmetric, the dipole moment will be zero as dipole moments cancel each other and the molecule will be non-polar.

As the molecule is asymmetric, the dipole moment will not be zero and the molecule will be polar.

Example: $NF_3$

Thus, we can say that $NF_3$ is a polar molecule.

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3 years ago

What is the pH of pure water at 40.0Â°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233

Sergeeva-Olga [200]

Answer:

PH= 6.767 (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

$[H_{3}O^{+} ] [OH^{-} ] = Kw = 2.92*10^{-14} M^{2} \\\\$

at 40ºC

$[H_{3}O^{+} ] = [OH^{-} ]$

$[H_{3}O^{+} ]^{2} = 2.92*10^{-14} M^{2}$

$[H_{3}O^{+} ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M$

$PH= -log10[H_{3}O^{+} ] = -log10(1.71*10^{-7} ) = 6.767$

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2 years ago

What is one molar volume of the gas ammonia (nh3) at stp?

Sedbober [7]

<span>The molar volume of ammonia at standard temperature and pressure (STP) is 22.4L. This is the standard molar volume of any gas at these conditions.</span>

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2 years ago

Read 2 more answers