For a comparison of the nucleus 5626fe, the density of the nucleus 112 48cd is mathematically given as the same.
n(Cd) / n(Fe)=1
<h3>What is the density of the nucleus 112 48cd?</h3>
Generally, the equation for the density is mathematically given as
d=\frac{A}{4/3}\piR^3
Therefore
n(Cd) / n(Fe) = [A (Cd) / (A Fe) ] * [ R (Fe) / R (Cd)]^3
n(Cd) / n(Fe)= (112 / 56 ) * (1/1.26)3
n(Cd) / n(Fe)=1
In conclusion, The ratio of n(Cd) = n(Fe) is 1, hence same
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brainly.com/question/14010194
<span>The particles are far apart from each other.</span>
Answer:
The correct option is;
The electronegativity increases
Explanation:
The electronegativity is the measure of an atom's ability to attract a shared electron pair. The electronegativity of an atom is dependent on the atom's atomic number and the separation distance between the electrons in the valence shell and the positively charged nucleus such that an increase in the atomic number results in an increase in electronegativity and an increase in the distance between the valence electrons and the nucleus, leads to a decrease in electronegativity.
Nuclear Fusion is the answer to the question who posted.
Answer:
In my opinion, I think its 2
Explanation:
