All categories

3 years ago

All cells _____.

1 answer:

7 0

The answer is the fourth choice, or Have membrane-bound organelles. Hope this helps you!

Please mark as Brainliest if this was correct!

-Belle

You might be interested in

Large cigars contain ________ grams of tobacco compared to small cigars that contain about 1 gram of tobacco.

miskamm [114]

D is the answer hope i helped

7 0

3 years ago

Write a short story in about 150 to 200 words based on the image given below

antoniya [11.8K]

Dude, writing someone else’s story or essay isn’t allowed, so i’ll just give some pointers

so the dude on the throne, a monarch, most likely the king, has a diamond or some other precious object in his hand. meanwhile, there’s a dude sitting on the floor, he looks unhappy, distressed, and maybe a little surprised. so what do you think happened to get to this point? what or who gave the king the diamond? why is the dude on the floor upset? then what’s going to happen? what’s the upset dude gonna
do? what’s the king gonna do? think of answers to the questions and it should start to form

6 0

3 years ago

Citric acid is often used as an acidity regulator in hot water canning of tomatoes. At 25°C it has Kat 7.4x10- and A.Hº = +4.1 k

gavmur [86]

Answer:

The rate constant at T = 100 C is 1.0*10⁻³

Explanation:

The Arrhenius equation relates two rate constants K1 and K2 measured at temperatures T1 and T2 as shown below:

$ln\frac{K_{2}}{K_{1}}=\frac{\Delta H^{0}rxn}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})$

here, ΔHrxn = standard enthalpy change of the reaction

R = gas constant

From the given information:

K1 = 7.4*10^-4

T1 = 25 C = 25+273 = 298 K

T2 = 100 C = 100+273 = 373K

ΔH°=4.1kJ/mol

$ln\frac{K_{2}}{7.4*10^{-4}}=\frac{4.1 kJ/mol}{0.08314kJ/mol.K}(\frac{1}{298}-\frac{1}{373})K$

K2 = 1.03*10⁻³

6 0

3 years ago

What makes the color of a fire work

exis [7]

Answer:

The use of metal salts. some of the compound produce intense colors when they are burned

4 0

3 years ago

For the reaction, 2cr2+ + cl2(g) ---> 2cr3+ + 2cl- e cell (standard conditions) = 1.78v calculate ecell (standard conditions)

PolarNik [594]

Answer:

-1.78 V

Explanation:

There are several rules required to calculate the cell potential:

given standard cell potential, we may reverse the equation: the products of a given reaction become our reactants, while reactants become our products in the reversed equation. For a reversed equation, we change the sign of the cell potential to the opposite sign;
if we multiply the whole equation by some number, this doesn't influence the cell potential value. It only produces a different expression in the equilibrium constant.

That said, notice that the initial reaction with respect to the final reaction is:

reversed: chromium(III) cation and chloride anion become our reactants as opposed to the products in the initial reaction, so we change the sign of the cell potential to a negative value of -1.78 V;
each coefficient is multiplied by a fraction of $\frac{1}{2}$ . It doesn't influence the value of the cell potential.

Thus, we have a cell of E = -1.78 V.

3 0

3 years ago