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puteri [66]
3 years ago
15

What is the double bond of XeF4

Chemistry
1 answer:
irina1246 [14]3 years ago
4 0
I think it’s 4 bonding correct me if I’m wrong
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Scientists have created an exact scale replica of a rover currently found on Mars and a miniature 3D landscape identical to that
igomit [66]

Answer:

D. It can be analyzed and shown to be reliable or un-reliable.

Explanation:

Trying the model out here on earth gives them a chance to observe what it would look like out there.

This will give them the chance to analyze the effectiveness of the rover and see if it can be reliable or not and if necessary adjustments should be made.

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3 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

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Isolate the lab immediately  mercury can be easily tracked throughout a lab by people walking on spill. laboratory staff can safely clean up small spill  . don't stamp on small pieces . carefully inspect the bench tops and floors before sitting. to  avoid hurting .

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