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tankabanditka [31]
4 years ago
10

A student is investigating temperature changes at a nature preserve on a hot, clear day. Each hour, the student takes two temper

atures: one over the ground, and one over the water of a lake. During this investigation, which observation is the student MOST LIKELY to make?
Group of answer choices

Air over the lake will reach its highest temperature later in the day and will stay warm longer than air over the ground.

Air over the lake will reach its highest temperature earlier in the day and will stay warm longer than air over the ground.

Air over the lake will reach its highest temperature later in the day and will cool off more quickly than air over the ground.

Air over the lake will reach its highest temperature earlier in the day and will cool off more quickly than air over the ground.
Physics
1 answer:
Sergio [31]4 years ago
7 0

As per the information given, there's most probability that the air over the lake will reach its highest temperature later in the day and will stay warm longer than air over the ground.

Answer: Option A

<u>Explanation:</u>

According to the concepts of the specific heats capacity of matter; it is observed that water possesses high specific heats capacity as compared to metals and other solids. Water takes much more time to absorb heat from the atmosphere and the same way takes time while releasing it into the atmosphere.

Whereas, solids and most metals have the tendency to quickly absorb and release the heat. Hence, it seems that the student may observe the rise in temperature for the air over the water lake later in the day which will stay warm longer than the air over the ground.

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kaheart [24]
<span>(a) How fast is it moving when it reaches 12.0 m?
To determine the velocity as it reaches 12.0 m, we use one of the kinematic equations,
</span>V^2 = Vo^2 + 2gh 
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<span>           g = -9.8 m/s^2 </span>
<span>           h = 12.0 m. </span>
V^2 = 20^2 + 2(-9.8)(12.0) 
<span>V^2 = 164.8
V = 12.84 m/s

(b) How long is required to reach this height?
 To determine the maximum height, we use the same equation we used above,
</span>V^2 = Vo^2 + 2gh 
where Vo = 20 m/s. 
           g = -9.8 m/s^2
           V = 0 (since at the maximum height velocity is zero) 
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(c) Why are there two answers for (b)?
There are two answers for b because it would travel a distance up and travel a distance down.</span>
5 0
3 years ago
Read 2 more answers
Suppose that a siren makes a sound reaching 120 decibels, but a wolf’s howl only reaches 90 decibels. 120 dB is how many times l
MakcuM [25]

Answer:

I₁/I₂ = 1000

Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.

Explanation:

First, we need to calculate the intensity of both the sounds. The formula for sound level is given as:

L = 10 log[I/I₀]

where,

L = Sound Level in dB

I = Intensity of sound

I₀ = Reference intensity = 10⁻¹² W/m²

<u>FOR SOUND OF SIREN:</u>

L = 120 dB

I = I₁ = ?

Therefore,

120 = 10 log[I₁/10⁻¹²]

log[I₁/10⁻¹²] = (120)/10

log[I₁/10⁻¹²] = 12

I₁/10⁻¹² = 10¹²

I₁ = (10¹²)(10⁻¹²)

I₁ = 1

<u>FOR SOUND OF WOLF'S HOWL:</u>

L = 90 dB

I = I₂ = ?

Therefore,

90 = 10 log[I₂/10⁻¹²]

log[I₂/10⁻¹²] = (90)/10

log[I₂/10⁻¹²] = 9

I₂/10⁻¹² = 10⁹

I₂ = (10⁹)(10⁻¹²)

I₂ = 10⁻³

Now, we divide the intensities:

I₁/I₂ = 1/10⁻³

I₁/I₂ = 10³

<u>I₁/I₂ = 1000</u>

<u>Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.</u>

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uysha [10]
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7 0
3 years ago
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tatuchka [14]

Answer:

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294.3sin\theta = 20

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4 years ago
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