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arsen [322]
3 years ago
11

Suppose that a siren makes a sound reaching 120 decibels, but a wolf’s howl only reaches 90 decibels. 120 dB is how many times l

ouder than 90 dB? Answer: 1000 times
Physics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

I₁/I₂ = 1000

Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.

Explanation:

First, we need to calculate the intensity of both the sounds. The formula for sound level is given as:

L = 10 log[I/I₀]

where,

L = Sound Level in dB

I = Intensity of sound

I₀ = Reference intensity = 10⁻¹² W/m²

<u>FOR SOUND OF SIREN:</u>

L = 120 dB

I = I₁ = ?

Therefore,

120 = 10 log[I₁/10⁻¹²]

log[I₁/10⁻¹²] = (120)/10

log[I₁/10⁻¹²] = 12

I₁/10⁻¹² = 10¹²

I₁ = (10¹²)(10⁻¹²)

I₁ = 1

<u>FOR SOUND OF WOLF'S HOWL:</u>

L = 90 dB

I = I₂ = ?

Therefore,

90 = 10 log[I₂/10⁻¹²]

log[I₂/10⁻¹²] = (90)/10

log[I₂/10⁻¹²] = 9

I₂/10⁻¹² = 10⁹

I₂ = (10⁹)(10⁻¹²)

I₂ = 10⁻³

Now, we divide the intensities:

I₁/I₂ = 1/10⁻³

I₁/I₂ = 10³

<u>I₁/I₂ = 1000</u>

<u>Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.</u>

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