Answer:
Luis’s, because he flipped the inequality sign when he subtracted
Step-by-step explanation:
7.2b + 6.5 > 4.8b – 8.1.
Amelia started by subtracting 7.2b from both sides to get
6.5 > –2.4b – 8.1
Correct
Luis started by subtracting 4.8b from both sides to get
2.4b + 6.5 < – 8.1
Incorrect
Shauna started by subtracting 6.5 from both sides to get
7.2b > 4.8b – 14.6
Correct
Clarence started by adding 8.1 to both sides to get
7.2b + 14.6 > 4.8b
Correct
Luis’s is incorrect because he flipped the inequality sign when he subtracted
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
If it is a rhombus then you know each side is the same length, so only have to work out one side. To do this you have to use Pythagoras' theorem (a^2 + b^2 = c^2)
So take two sets of coordinates, for example, (0,3) and (5,3), a and b represent the height difference and the length difference. Therefore (5-0)^2 + (3-3)^2 = c^2
c^2 = 25
c = 5 , which would be the side of the rhombus
Answer:
3/5
Step-by-step explanation:
Answer:
Step-by-step explanation:
<h3>Hope it is helpful....</h3>
