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Colt1911 [192]
3 years ago
6

2. A 4-kg gun shoots a 0.1-kg bullet at 400 m/s. Find the recoil speed of the gun.

Physics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:10m/s

Explanation:

M=mass of gun=4kg

U=recoil velocity of gun

m=mass of bullet=0.1kg

V=velocity of bullet=400m/s

M x U=m x V

4 x U=0.1 x 400

4xU=40

Divide both sides by 4

(4xU)/4=40/4

U=10m/s

Recoil velocity=10m/s

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The weight of the meterstick is:
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from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
M_w = W d_1 = (1.97 N)(0.10 m)=0.20 Nm

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
(mg) d_2 = 0.20 Nm
from which we find the value of d2:
d_2 =  \frac{0.20 Nm}{mg}= \frac{0.20 Nm}{(0.5 kg)(9.81 m/s^2)}=0.04 m

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4 0
4 years ago
What is the approximate efficiency of the engine?
Elodia [21]

Answer:91% I think

Explanation:

8 0
3 years ago
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Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea
madreJ [45]
In order to answer this exercise you need to use the formulas

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3 years ago
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A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.900 fg (where a femtogra
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Answer:

9.73 x 10⁻¹⁰ m

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Δp = mΔV

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Δ X = h / 4π x 1 /  54 x 10⁻²⁷

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3 years ago
Me podrían dar la respuesta y el proceso?
Nat2105 [25]

Answer:

I don’t understand Espanol

Explanation:

sorry

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