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Colt1911 [192]
3 years ago
6

2. A 4-kg gun shoots a 0.1-kg bullet at 400 m/s. Find the recoil speed of the gun.

Physics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:10m/s

Explanation:

M=mass of gun=4kg

U=recoil velocity of gun

m=mass of bullet=0.1kg

V=velocity of bullet=400m/s

M x U=m x V

4 x U=0.1 x 400

4xU=40

Divide both sides by 4

(4xU)/4=40/4

U=10m/s

Recoil velocity=10m/s

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Slav-nsk [51]

Answer:

The procedure involves severing the corpus callosum, the main bond between the brain's left and right hemispheres. ... This impairment can result in split-brain syndrome, a condition where the separation of the hemispheres affects behavior and agency.

Explanation:

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3 years ago
200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?
ArbitrLikvidat [17]

Answer:

 20N

Explanation:

Given parameters:

Work done  = 200J

Distance moved  = 10m

Unknown:

Amount of force applied  =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

      Work done  = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

           Force  = \frac{Work done}{distance}

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4 years ago
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6 0
2 years ago
Based on the evidence for the impact theory, what was the most probable order of events for the collision that led to the format
anastassius [24]

Answer:

Answered

Explanation:

According to the impact theory, a glancing collision between a Mars-sized object and Earth led to the formation of the Moon. The iron core of Earth had formed before this collision, leading to the similarity between the composition of the Moon and Earth's mantle. After the collision, any iron core of the Mars-sized object would have been left behind on Earth and eventually merged with Earth's core. The Moon then formed out of the debris thrown into space by the collision.

5 0
3 years ago
A series LRC circuit consists of a 12.0-mH inductor, a 15.0-µF capacitor, a resistor, and a 110-V (rms) ac voltage source. If th
finlep [7]

Answer:

61.85 ohm

Explanation:

L = 12 m H = 12 x 10^-3 H, C = 15 x 10^-6 F, Vrms = 110 V, R = 45 ohm

Let ω0 be the resonant frequency.

\omega _{0}=\frac{1}{\sqrt{LC}}

\omega _{0}=\frac{1}{\sqrt{12\times 10^{-3}\times 15\times 10^{-6}}}

ω0 = 2357 rad/s

ω = 2 x 2357 = 4714 rad/s

XL = ω L = 4714 x 12 x 10^-3 = 56.57 ohm

Xc = 1 / ω C = 1 / (4714 x 15 x 10^-6) = 14.14 ohm

Impedance, Z = \sqrt{R^{2}+\left ( XL - Xc \right )^{2}}

Z = \sqrt{45^{2}+\left ( 56.57-14.14 )^{2}} = 61.85 ohm

Thus, the impedance at double the resonant frequency is 61.85 ohm.

7 0
3 years ago
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