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BigorU [14]
3 years ago
12

If you wanted to decrease the gravitational force between two objects, what would you do?

Physics
2 answers:
Irina-Kira [14]3 years ago
8 0
<span>A. Increase the distance between the two objects</span>
oee [108]3 years ago
6 0

A.    Increase the distance between two objects

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The perceived pitch of a tone is largely determined by its
soldier1979 [14.2K]

The perceived pitch of a tone is largely determined by its frequency

<h3>What is  frequency ?</h3>

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated.

The period is the reciprocal of the frequency since it is the length of time for one cycle in a repeating occurrence. If a heart beats 120 times per minute (2 hertz), for instance, its period, T—the space between beats—is half a second. In science and engineering, frequency is a crucial metric for describing the temporal rate of change seen in oscillatory systems.

To learn more about frequency  from the given link:

brainly.com/question/27216648

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3 0
2 years ago
How would I calculate the X from a known velocity when launching a ball off a table?
Anon25 [30]
Here are the steps you would need to follow:

#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.

With this information in front of you, you'll have a much better chance
of answering the question.

With none of it in front of me, I have no chance at all.
4 0
3 years ago
Read 2 more answers
To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to
dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

y=ut+\frac{1}{2} gt^2

Where g=9.8 m/s^2

40=0+\frac{1}{2}(9.8)t^2=4.9t^2

t^2=\frac{40}{4.9}

t=\sqrt{\frac{40}{4.9}}=2.86 s

x=v_x\times t

30=v_x(2.86)

v=v_x=\frac{30}{2.86}=10.49 m/s

By work energy theorem

Change in kinetic energy=Work done= mgh-W

\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W

\frac{1}{2}(3)(10.49)^2-0=676.2-W

W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0
3 years ago
A spaceship is moving at 0.74 c (0.74 times the speed of light) with respect to the earth. An observer on the spaceship measures
olya-2409 [2.1K]

Answer:

The time interval is 22.76 hr.

Explanation:

Given that,

Time = 30 hrs

Speed = 0.74c

We need to calculate the time interval measured in earth frame

Using formula of time dilation

\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}

Where, \Delta t = time interval measured in earth frame

\Delta t_{0}=proper time interval

Put the value into the formula

\Delta t=\dfrac{30}{\sqrt{1-\dfrac{0.74c^2}{c^2}}}

\Delta t=\dfrac{30}{\sqrt{1-(0.74)^2}}

\Delta t=\dfrac{30}{0.6726}

\Delta t=44.60\ hr

We need to calculate the proper time interval when the velocity is 0.86c

Using formula of time dilation

44.60=\dfrac{\Delta t_{0}}{\sqrt{1-\dfrac{0.86c^2}{c^2}}}

\Delta t_{0}=44.60\times\sqrt{1-(0.86)^2}

\Delta t_{0}=22.76\ hr

Hence, The time interval is 22.76 hr.

3 0
3 years ago
Q 1. How does friction affect the mechanical energy of a system? Q 2. A roller coaster is at the stop of a hill and rolls to the
Vaselesa [24]

Answer:

  1. Friction lowers (decreases) the kinetic energy which in turn decreases the mechanical energy of a system.
  2. At the top of the second hill.

Explanation:

8 0
3 years ago
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