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3 years ago

If you wanted to decrease the gravitational force between two objects, what would you do?

Physics

2 answers:

Irina-Kira [14]3 years ago

8 0

A. Increase the distance between the two objects

oee [108]3 years ago

6 0

A. Increase the distance between two objects

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Can somebody help please !!!!

Nataly [62]

Vector A is of magnitude 12 m and it makes an angle of 37 degree with Y axis

So here we can say that

$\frac{A_x}{A} = sin37$

$A_x = A sin37$

$A_x = 12 sin37$

$A_x = 7.22 m$

Similarly we have

$\frac{A_y}{A} = cos37$

$A_y = A cos37$

$A_y = 12 cos37$

$A_y = 9.58 m$

So here we have

$A_y = 9.58 m, A_x = 7.22 m$

option A is correct

3 0

3 years ago

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

Yuri [45]

Answer:

$q = 2.067 \times 10^{-5}\ C$

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

$q =\dfrac{mg}{E}$

$q =\dfrac{0.00141 \times 9.81}{670}$

$q = 2.067 \times 10^{-5}\ C$

Charge of the particle is equal to $q = 2.067 \times 10^{-5}\ C$

6 0

4 years ago

Consider a helium balloon with volume 2.1 L.

Anna11 [10]

Answer:

The net force is 26.52 N

Explanation:

Given that,

Volume of balloon = 2.1 L

Density of air = 1.29 kg/m³

Mass = 1.3 g

Density of helium $\rho'= 0.18\times10^{-3}\ g/cm^3$

(a). We need to calculate the buoyant force on the balloon

Using formula of buoyant force

$F_{b}=\rho V g$

Put the value into the formula

$F_{b}=1.29\times\times2.1\times9.8$

$F_{b}=26.54\ N$

(b). We need to calculate the net force

Using formula of net force

$F_{net}=F_{b}-(V\times\rho'+m)\times g$

$F_{net}=26.54-(2.1\times10^{-3}\times0.18\times10^{-3}+0.0013)\times9.8$

$F_{net}=26.52\ N$

Hence, The net force is 26.52 N.

6 0

3 years ago

After a light turns green , Lesly accelerates to 120 km/hr over 100 meters . What is her acceleration in m/s^2

Ivenika [448]

Answer:

5.55 m/s²

Explanation:

Initial velocity = 0
Final velocity = 120 km/hr = 33.3 m/s
Displacement = 100 m

Using Third law of Motion :-

$\longrightarrow$ 2as = v² - u²

$\longrightarrow$ 2*a* 100 = (33.33 m/s)²-0²

$\longrightarrow$ a = 200a = 1110.89

$\longrightarrow$ a = 1110.89/200

$\longrightarrow$ a = 5.55 m/s²

Symbols have their usual meaning .

**Edits are welcomed**

4 0

3 years ago

Help please!!! Do you think we always see the same side of the Moon?

Reika [66]

Answer:

yess

Explanation:

"The Moon orbits Earth once every 27.3 days and spins on its axis once every 27.3 days. This means that although the Moon is rotating, it always keeps one face toward us. Known as “synchronous rotation,” this is why we only ever see the Moon's nearside from Earth."

3 0

3 years ago