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BigorU [14]
3 years ago
12

If you wanted to decrease the gravitational force between two objects, what would you do?

Physics
2 answers:
Irina-Kira [14]3 years ago
8 0
<span>A. Increase the distance between the two objects</span>
oee [108]3 years ago
6 0

A.    Increase the distance between two objects

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Jamie decides to drop an egg that has a mass of 345 g off the top of a 8.2 m building. How fast will it be falling right before
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Answer:

13 m/s

Explanation:

Given:

Δy = 8.2 m

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a = 9.8 m/s²

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v² = (0 m/s)² + 2 (9.8 m/s²) (8.2 m)

v = 12.7 m/s

Rounded to two significant figures, the speed is 13 m/s.

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6 0
3 years ago
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The word that identifies the color of an object seen under ordinary daylight is:
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3 years ago
Two adjacent natural frequencies of an organ pipe are AMT determined to be 550 Hz and 650 Hz. Calculate (a) the M fundamental fr
allochka39001 [22]

Answer:

The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

Explanation:

Given that,

Frequency f = 550 Hz

Frequency f' = 650 Hz

We know that,

AMT pipe is open pipe.

(b). We need to calculate the length of the pipe

Using formula of organ pipe

f=\dfrac{nv}{2L}

For 550 Hz,

550=\dfrac{n\times340}{2L}...(I)

For 650 Hz,

650=\dfrac{(n+1)\times340}{2L}...(II)

From equation (I) and (II)

550-650=\dfrac{340}{2L}-\dfrac{340}{L}

L=\dfrac{340}{2\times100}

L=1.7\ m

(a). We need to calculate the fundamental frequency for n = 1

Using formula of  fundamental frequency

=f=\dfrac{n\lambda}{2L}

put the value of L

f=\dfrac{1\times340}{2\times1.7}

f=100\ Hz

Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

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3 years ago
When is the only time that an object has no gravitational potential energy
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