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zzz [600]
3 years ago
12

Different betweenof mass and weight​

Physics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

The differences are:

Mass:

1) It is the total amount of matter contained in a body.

2) It's SI unit is kilogram (kg).

3) It's measured by using beam balance

Weight:

1) It is the force which pulls an object towards the center of the earth.

2) It's SI unit is newton(n).

3) It's measured by using spring balance.

plz mark brainliest ✌️✌️

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you have two pendulums with cords that are exactly the same length. one is on earth (with an acceleration due to gravity of 9.81
olga55 [171]
From  T = 2π√(l/g).

Since the lengths are the same, so that is a constant.

T α 1/√g

So the period T is inversely proportional to the square root of gravity g.

So the one with a bigger gravity g would have a shorter period

and

the one with smaller gravity g would have a longer period.

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8 0
3 years ago
What type of force cause an object to accelerate??
Olin [163]
ANY force causes an object to accelerate, just as long as there are not
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Are you looking for the answer ... an "UNBALANCED" force ?
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8 0
3 years ago
The moon Phobos orbits Mars
shepuryov [24]

27.9816 \times 10^{3} s is the period of orbit.

<u>Explanation: </u>

The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:

                  \frac{T^{2}}{R^{3}}=\frac{4 \times \pi^{2}}{G \times M_{c e n t r a l}}

Where,

T is the period of the orbit

R is the average radius of orbit

G is gravitational constant  6.673 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}

Here, given data

M=6.23 \times 10^{23} \mathrm{kg}

R=9.38 \times 10^{6} \mathrm{m}

Substitute the given values, we get T as

      \frac{T^{2}}{\left(9.38 \times 10^{6}\right)^{3}}=\frac{4 \times(3.14)^{2}}{\left(6.673 \times 10^{-11}\right) \times 6.23 \times 10^{23}}

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Taking square root, we get

       T=27.9816 \times 10^{3} s

4 0
3 years ago
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Olegator [25]

-- "Declination zero" means the object is in the sky at some point directly over the Earth's equator.  

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5 0
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Answer:

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Explanation:

7 0
3 years ago
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