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3 years ago

All of the following are a characteristic of science except

2 answers:

8 0

No. It is D. Science is actually testable. That is the purpose of the scientific method: to TEST a theory. For something to be considered science, you must be able to observe, ask questions, develop questions, and test them. Thefore, it is a process. Lastly, yes. Science is a body of knowledge. It's a subject field that covers many things and numerous sub areas.

Lubov Fominskaja [6]3 years ago

4 0

Answer: d

Explanation:

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What must you do if you plan to exercise everyday

kumpel [21]

Answer: set up a reminder so you won't forget also try clearing your schedule so you can have more time

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4 years ago

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A hiker begins a trip by first walking 25.0 km southeast from her car. She stops and sets up her tent for the night. On the seco

Sunny_sXe [5.5K]

Answer:

(a)

$x_1=17.68km\\y_1=-17.68km\\x_2=20km\\y_2=34.64km$

(b) $r=41.32km$

$\alpha =24.23^o$

Explanation:

Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

First day:

25.0 km southeast, which implies $45^o$ south of east. The y-component will be negative and the x-component will be positive.

$x_1=25cos45^o=17.68km$

$y_1=-25sin45^o=-17.68km$

Second day:

She starts off at the stopping point of last day. This time, both the y- and x-components are positive.

$x_2=40cos60^o=20km$

$y_2=40sin60^o=34.64km$

Therefore, total displacements:

$x=x_1+x_2=(17.68+20)km=37.68km$

$y=y_1+y_2=(-17.68+34.64)km=16.96km$

Magnitude of displacements,

$r=\sqrt{x^2+y^2}=41.32km$

Direction,

$\alpha =tan^{-1}(\frac{y}{x})=24.23^o$

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4 years ago

Who was the first person to discover wormholes?

valentinak56 [21]

The first who discovered The Einstein Roses bridge it was discovered by Ludwig flamm in 1916 a few months after Schwarzschild published his solution and was rediscovered by Albert Einstein and his colleague Nathan Rosen which was published then in 1935

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3 years ago

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What type of galaxy is M82 based on its appearance in the visible-light view?

SSSSS [86.1K]

<h2>Answer: irregular</h2>

According to Hubble galaxies are classified into elliptical, spiral and irregular.

It should be noted this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.

The classification is as follows:

1. Elliptical galaxies: Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.

2. Spiral galaxies: They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.

3. Irregular Galaxies: Galaxies that do not have well-defined structure and symmetry.

In this context, galaxy M82 does not match with the first two types of galaxies, because it has not a defined shape.

Therefore, M82 is an irregular galaxy.

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3 years ago

What is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k,

WITCHER [35]

The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force. This is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k, is a very large number

Answer: The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force.

<u>Explanation: </u>

We know that the universal formula for the estimation of gravitational force is,

$F=G \times\left(\frac{m_{1} \times m_{2}}{r^{2}}\right)$

Where,

F, Gravitational force, $m_{1} \text { and } m_{2}$ - objects masses r- The relative distance between the two objects

G, Gravitational Constant $6.67 \times 10^{-11} \frac{N m^{2}}{k g^{2}}$

And, the electrostatic force between two scalar charges according to the Coulomb’s law is,

$F=k \times\left(\frac{q_{1} \times q_{2}}{r^{2}}\right)$

F, Electrostatic force between two charges, $q_{1} \text { and } q_{2}$ - Two scalar charges, r - The relative distance between two scalar charges, k- Coulomb’s constant $8.987 \times 10^{9} \frac{N m^{2}}{c^{2}}$

Now, on comparing the values of G and k, we can easily evaluate that eventually, the gravitational force will be lesser than the coulomb’s force.

Besides this, we can also judge this fact through various examples such as, a balloon rubbed with a cloth, easily sticks to the wall for some time. Opposing the gravitational force of the Earth which is not the case with the normal balloon.

It drops without having the electrostatic force between the wall and the balloon. This shows that the gravitational force draws lesser impact on objects as compared to the electrostatic force.

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3 years ago

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