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2 years ago

an ice Puck travels 18 m in 3 S before it slides into the goal what is the speed of the traveling puck

Physics

2 answers:

USPshnik [31]2 years ago

6 0

Answer:

<h2>Given :-</h2>

Distance travelled (D) = 18 m
Time taken (T) = 3 second

Speed

<h2>Solution :-</h2>

As we know that

$\sf Speed = \dfrac{Distance}{Time}$

$\sf \: Speed = \dfrac{18}{3}$

Cancelling both by 3

$\sf \: Speed = 6 \: mps$

DiKsa [7]2 years ago

4 0

Answer:

$\boxed {\boxed {\sf 6 \ meters \ per \ second}}$

Explanation:

Speed can be found by dividing the distance by the time.

$s=\frac{d}{t}$

The distance is 18 meters and the time is 3 seconds.

$d= 18 \ m \\t= 3 \ s\\$

Substitute the values into the formula.

$s=\frac{18 \ m }{ 3 \ s }$

Divide.

$s= 6 \ m/s$

The speed of the puck is 6 meters per second.

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Ms. Mary Mack walked around her block from her house for 200 meters. She arrived back at her house in 15 minutes. What was her d

inysia [295]

Answer:

d = 0 [m]

Explanation:

Displacement is understood as the length and direction that a body travels to move from an initial point to an endpoint.

This displacement is represented with a vector or straight line that indicates the distance of the displacement and its length.

This displacement in an easier way to understand. It is the distance between the start point and the endpoint of the journey. Since the second point is equal to the first point, since Mary returns to the same place, there is no difference between the displacement.

Therefore the displacement is zero.

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2 years ago

A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi

Artist 52 [7]

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm$

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

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2 years ago

A school bus is headed on a field trip to LA traveling at 55 mph. Robert is

Scorpion4ik [409]

Answer: 63 miles per hour

i think

Explanation:

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2 years ago

A firefighter of mass 81 kg slides down a vertical pole with an acceleration of 3 m/s 2 . The acceleration of gravity is 10 m/s

natima [27]

Answer:

The force of friction that acts on him is

$F_k=567N$

Explanation:

The firefighter with an acceleration of 3m/s^2 take the gravity acceleration as 10m/s^2 isn't necessary to know the coefficient of friction just to know the force of friction:

$F=m*a$