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MaRussiya [10]
2 years ago
12

an ice Puck travels 18 m in 3 S before it slides into the goal what is the speed of the traveling puck ​

Physics
2 answers:
USPshnik [31]2 years ago
6 0

Answer:

<h2><u>Given</u><u> </u><u>:</u><u>-</u></h2>
  • Distance travelled (D) = 18 m
  • Time taken (T) = 3 second
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u></h2>

Speed

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

As we know that

\sf Speed = \dfrac{Distance}{Time}

\sf \: Speed =  \dfrac{18}{3}

Cancelling both by 3

\sf \: Speed = 6 \: mps

DiKsa [7]2 years ago
4 0

Answer:

\boxed {\boxed {\sf 6 \ meters \ per \ second}}

Explanation:

Speed can be found by dividing the distance by the time.

s=\frac{d}{t}

The distance is 18 meters and the time is 3 seconds.

d= 18 \ m \\t= 3 \ s\\

Substitute the values into the formula.

s=\frac{18 \ m }{ 3 \ s }

Divide.

s= 6 \ m/s

The speed of the puck is <u>6 meters per second.</u>

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Assume that Parker Company will receive SF200,000 in 360 days. Assume the following interest rates:
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Answer:

b.  $96,914

Explanation:

360-day borrowing rate = 5%

spot rate = 0.48

360-day deposit rate  = 6%

Borrow at the rate of 5% to get

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Convert at the spot rate of $0.48 to get

190,476.19*0.48 = $91,428.57

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3 years ago
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aliya0001 [1]

Answer:

v_{f1}=-0.345m/s , v_{f2}=0.23m/s

Explanation:

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p_i=p_f

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1/2*m_1*v_1^2+1/2*m_2*v_2^2=1/2*m_1*v_{f1}^2+1/2*m_1*v_{f2}^2

Two equations and two variables to find solve to both finals velocities:

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