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3 years ago

How many oxygen atoms are contained in 2.74 g of Al2(SO4)3?

Chemistry

2 answers:

skad [1K]3 years ago

4 0

Answer:

either 12 or 24

Explanation:

abruzzese [7]3 years ago

3 0

Answer:

5.79 × 10^23 Oxygen atoms

Explanation:

Number of Oxygen atom in the compound = 4×3 = 12

Molar mass of Al2(SO4)3 = 342 g/mol.

No of mole = mass/molar mass = 2.74/342 = 8.01×10^-03 mole

2.74g of Al2(SO4)3 × 1 mole of Al2 (SO4)3 / 342g of Al2 (SO4)3 * 12 mole of Oxygen/ 1mole of Al(SO4)3 * 6.02×10^23 Oxygen atom/ 1 mole of Oxygen

= 5.79×10^23 Oxygen atoms

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user100 [1]

Answer:

Option A is correct, there will be no N2 left in the flask

Explanation:

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