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ch4aika [34]
3 years ago
15

A 20-kg bicycle carrying a 50-kg girl is traveling at a speed of 8 m/s. What is the kinetic energy of the girl

Chemistry
1 answer:
finlep [7]3 years ago
6 0

Answer:

The answer to your question is Ke = 2240 J

Explanation:

Data

mass of the object = 20 kg

mass of the girl = 50 kg

speed = 8 m/s

Kinetic energy = Ke = ?

Formula

Ke = 1/2 mv²

Process

Kinetic energy is due to the movement of an object.

1.- Calculate the total mass

Total mass = 20 + 50 = 70 kg

2.- Substitution

Ke = 1/2(70)(8)²

3.- Simplification

Ke = 1/2(4480)

4.- Result

Ke = 2240 J

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pav-90 [236]

Answer:

As a substance changes from a solid to a liquid to a gas, its molecules first the molecules are moving fast enough, they are able to "escape." They leave the surface of the liquid as gas molecules. Evaporation is not the only process that can change a substance from a liquid to a gas. The same change can occur through boiling.

Explanation:

6 0
3 years ago
Please someone help mee
Nikitich [7]

Answer:

13.9kj/mol

Explanation:

h = 891 -(393.5 +2*241.8)=1768.1=13.9kj/mol

8 0
3 years ago
In the reaction h2so4 + na2co3 → na2so4 + co2 + h2o 14.5 g of water is collected. what is the molarity of sulfuric acid if 1.78
Yuliya22 [10]
H2SO4 + Na2CO3  → Na2SO4 + CO2 + H2O

The molarity  of  sulfuric acid  if  1.78  L  were used  in the   above reaction is
 0.453 M  (answer 2)

      Calculation
find the  moles of water  produced  = mass/molar  mass

=   14.5 g /18 g/mol  = 0.806  moles

by use of of mole ratio  between  H2So4  to H2O   which is 1:1  the    moles    of   H2SO4   is also =  0.806   moles


Molarity  of H2SO4 is therefore =    moles/volume  in   liters

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8 0
3 years ago
At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oC. What will be the temperature at 1.13 atmosphere
Inessa [10]

Answer:  Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

{P_1\times T_1}={P_2\times T_2}

where,

P_1 = initial pressure of gas   = 1.00 atm

P_2 = final pressure of gas  = 1.13 atm

T_1 = initial temperature of gas  = 100^0C=(100+273)K=373K K

T_2 = final temperature of gas  = ?

{1.00\times 373}={1.13\times T_2}

T_2=330K

Therefore, the final temperature of the gas will be 330 K.

7 0
3 years ago
Use Target Reading Skills After you read the section, reread the paragraphs that contain definitions of Key Terms. Use all of th
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