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3 years ago

2. PART B: Which detail from the text best supports

Chemistry

1 answer:

uranmaximum [27]3 years ago

4 0

Answer:

Explanation:

b is not talking about vaccines and d is against vaccines

Hope this helps!

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which best describes ionization energy? a. energy needed to add an electron to a neutral atom in the gas phase b. energy needed

SVEN [57.7K]

c. energy needed to remove an electron from an atom or ion in the gas phase

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3 years ago

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Calculate the standard cell potential of the following cell at 25°C. Sn(s) | Sn2+(aq) || Cu2+(aq) | Cu(s).

Semmy [17]

Answer:

0.48 V

Explanation:

Usually in the cell notation, the left side shows oxidation. So,

Oxidation half reaction:

$Sn_{(s)}\rightarrow Sn^{2+}_{(aq)}+2e^-$ $E^o_{ox}=-E^o_{red}=-(-0.14\ V)=0.14\ V$

Reduction half reaction:

$Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}$ $E^o_{red}=0.34\ V$

$E^o_{cell}=E^o_{ox}+E^o_{red}= (0.14+0.34)\ V=0.48\ V$

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3 years ago

Why is Potassium not used in school laboratory

densk [106]

<h3>Because it is harmful for school environment.</h3>

Potassium Metal Is Explosive— Do Not Use It! The reaction of sodium with water is a spectacular and essential classroom demonstration. Many teachers want to show also the more violent reaction of potassium. We propose not to do so because explosions can happen even before the metal is in contact with water.

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3 years ago

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An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions at room

Andrej [43]

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

$E=E\°-\frac{0.0591}{n} log(Q)$

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

$Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V$

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

$E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V$

Beat regards!

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3 years ago

Calculate the [oh] for 0.46 Hcl

Bad White [126]

Answer:

2.17 e -14

Explanation:

A strong acid like HCl ionize 100 % in water so [H3O+] = 0.46 M

[OH-] = Kw / [H3O+]

= 1.0 e -14 / 0.46

= 2.17 e -14

3 0

3 years ago