The correct balanced chemical equation which occur when methane burn in oxygen gas is
CH4 + 2O2 --> 2H2O +CO2 (answer D)
when methane is burned in presence of oxygen gas it produces carbon(IV) oxide and water and energy,that is 1 mole of CH4 reacted with 2 moles of O2 to form 2 moles of water and 1 mole of CO2 and enegy. This energy make the methane to be used as fuel.
Answer:
Option (B) 7
Explanation:
C3H6O2(l) + O2(g) → CO2(g) + H2O(l)
To know the coefficient of O2 in the above equation, let us balance the equation.
The above equation can be balance as follow:
C3H6O2(l) + O2(g) → CO2(g) + H2O(l)
There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:
C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)
There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:
C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)
Multiply through by 2
2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)
Now, the equation is balanced.
From the balanced equation above, the coefficient of O2 is 7.
C. HNO₃(aq) + KOH(aq) → KNO₃(aq) + H₂O
Answer: -
The acceleration due to gravity at height r = a = GM/r²
Rearranging
r² = GM /a
= (6.674 x 10⁻¹¹ x 5.972 x 10²⁴ ) / 5
r = 8.917 x 10⁶ m
r = 8917 Km
Now Radius of earth = 6371 Km
So height = 8917 - 6371 = 2546 Km
The moles of O2 are needed to react completely with 1.00 mol of C₂H₂ is 5 mol , 0.23 moles of C₂H₂ are needed to form 0.46 mol of CO₂ .
<h3>What is a Balanced Reaction ?</h3>
A balanced reaction is a reaction in which the number of atoms present in the reactants is equal to the number of atoms in the products.
It is given in the question that
the combustion of Acetylene is given by
2 H―C≡C―H + 5 O₂ → 4 CO₂ + 2 H₂O
Given moles of Acetylene = 1 mol
Moles of oxygen needed = 5 mol
as the mole fraction of Acetylene to Oxygen is 1 :5
The mole of Acetylene needed to form 0.46 mol of CO₂ is ?
mole fraction of CO₂ to Acetylene is 4:2
Therefore 0.23 moles of CO₂ is required.
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