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3 years ago

ILL MARK YOU AS BRAINLIEST, RATE YOU A 5, AND THANK YOU! 30 PTS!

Chemistry

2 answers:

asambeis [7]3 years ago

6 0

Answer:

c is the answer to your question

gavmur [86]3 years ago

3 0

Answer:

Explanation:

One of the parents most likely has the dominant gene while the other has the dominant and recessive. One of the offspring will be green.

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How does the state of atoms in a neon light change when light is emitted?

Blababa [14]

The state of atoms in a neon light when light is emitted is loss of energy.

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2 years ago

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Which of the following is not a benefit of the water cycle?

BigorU [14]

Answer:

4th line

Explanation:

-water cycle helps regulate the temperature on the Earth.

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3 years ago

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a sample of hydrogen gas (h2) is mixed with water vapor (h2o (g)). the make sure has a total pressure of 811 torr, and the water

Alborosie

Answer:

$n=0.430molH_2$

Explanation:

Hello!

In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:

$p_T=p_H+p_w\\\\p_H=811torr-12torr=799torr*\frac{1atm}{760torr}\\\\p_H=1.05atm$

Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:

$PV=nRT\\\\n= \frac{PV}{RT}=\frac{1.05atm*10.0L}{0.082\frac{atm*L}{mol*K}*298K}\\\\n=0.430molH_2$

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6 0

3 years ago

What type of particle is emitted by each type of radioactive decay?

olya-2409 [2.1K]

C. alpha = nucleus of a helium atom

beta = electron

gamma = photon

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2 years ago

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VA 19.75-g sample was heated by 12.35 calories. The specific heat of the sample is 0.125 cal/g°C. What was the initial temperatu

SOVA2 [1]

Answer:

31.9 °C

Explanation:

The formula for the heat q absorbed by an object is

q = mCΔT where ΔT = (T₂ - T₁)

Data:

q = 12.35 cal

m = 19.75 g

C = 0.125 cal°C⁻¹g⁻¹

T₂ = 37.0 °C

Calculations

(a) Calculate ΔT

q = mCΔT

12.35 cal = 19.25 g × 0.125 cal°C⁻¹g⁻¹ × ΔT

12.35 = 2.406ΔT °C⁻¹

ΔT = 12.35/(2.406 °C⁻¹) = 5.13 °C

(b) Calculate T₂

ΔT = T₂ - T₁

T₁ = T₂ - ΔT = 37.0 °C - 5.13 °C = 31.9 °C

The original temperature was 31.9 °C.

6 0

2 years ago