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Ivenika [448]
4 years ago
5

A glacier advances at 7.4 x 10^-6 cm/s

Physics
1 answer:
Sloan [31]4 years ago
6 0

Answer:

236.8 cm

Explanation:

1 yr = 365 days = (365×24×60×60) secs

= 32 × 10^6

distace = velocity × time

= 7.4 × 10^-6 × 32 × 10^6

= 236.8 cm

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Calculate the force, when a object acelerattes to 30 m/s^2 and have a mass of 40 kg
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Hello!

Use the <u>second law of Newton:</u>

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F = 1200 N

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3 years ago
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myrzilka [38]

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3 years ago
A 200.0 g block rests on a frictionless, horizontal surface. It is pressed against a horizontal spring with spring constant 4500
kenny6666 [7]

Answer:

 6 m/s

Explanation:

Given that :

mass of the block   m =  200.0 g  = 200 × 10⁻³ kg

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To determine the speed the block will be traveling when it leaves the spring; we applying the  work done on the spring as it is stretched (or compressed) with the kinetic energy.

i.e \frac{1}{2} kx^2  = \frac{1}{2} mv^2

kx^2 = mv^2

4500* 0.04^2 = 200*10^{-3} *v^2

7.2 =200*10^{-3}*v^{2}

v^{2}   =\frac{7.2}{200*10^{-3}}

v   =\sqrt{\frac{7.2}{200*10^{-3}}}

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is  6 m/s

5 0
4 years ago
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