Gravity is greater when there is

1 answer:

N76 [4]3 years ago

4 0

Gravity is greater when there is more mass and less distance between two objects

 m1m2
g = G---------
r²

Where G gravitational constant, m1 and m2 the two masses, and r the distance between their centers. This shows that as either mass increases, the gravitational force increases; or as the distance increases, the gravitational force decreases exponentially. T

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A person gives a shopping cart an initial push along a horizontal floor to get it moving, and then lets go. The cart travels for

mash [69]

Answer:

Only a backward force is acting, no forward force.

Explanation:

Once released from the initial push, in absence of friction, the shopping cart would continue moving forward at a constant speed forever.
As it would move at a constant speed, no net force would be acting on it.
So, if it is gradually slowing, there must be a net force producing an acceleration in a direction opposite to the movement.
This force is the kinetic friction force, and is the only force acting on the cart in the horizontal direction.
As any friction force, opposes to the relative movement between the cart and the horizontal floor, which means that is directed backward.
This is consistent with the direction of the acceleration of the cart.

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Hazardous solid wastes

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A street light is on top of a 8 foot pole. Joe,

zubka84 [21]

8/4 = y/y-x

8y - 8x = 4y

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4 years ago

What is the specific heat of a material that has a mass of 5 grams and increases 125ºC when it receives 150J of heat?

rjkz [21]

Answer:

0.24 ? I hope that was the answer you were looking for.

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A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc

marta [7]

This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so:

$v_{d} = \frac{J}{n\left | q \right |}$

The current I is any motion of charge from one region to another, so this is given by:

 $I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)$

The magnitude of the current density is:

$J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})$

Being:

$A=2mm^{2} = 2x10^{-6}m^{2}$

Finally, for the drift velocity magnitude vd, we find:

 $v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)$

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd

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3 years ago