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3 years ago

Calculate the force, when a object acelerattes to 30 m/s^2 and have a mass of 40 kg

Physics

2 answers:

Dafna1 [17]3 years ago

8 0

Answer:

1200

Explanation:

You have to multiply 30 times 40 from there you get your answer

30(40)=1200 that is your answer.Because you want to find your force.

F=1200N

M=40kg

A=30m/s^2

This are your answers.

Hope this helps:)

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faust18 [17]3 years ago

3 0

Hello!

Use the second law of Newton:

F = ma

Replacing:

F = 40 kg * 30 m/s^2

Resolving:

F = 1200 N

The force is 1200 Newtons.

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By definition, acceleration is (5 Points)

Dovator [93]

Acceleration is a change in speed and/or direction

Explanation:

The acceleration of an object is defined as the rate of change of velocity, mathematically:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time taken for the velocity of the object to change

We notice that velocity is a vector quantity, so it consists of:

- A magnitude, which is called speed

- A direction

Since acceleration is the rate of change in velocity, this means that the acceleration is non-zero whenever $\Delta v$ is non-zero, which means that either the speed AND/OR the direction of the velocity is changing.

For instance:

- For an object which is speeding up along a straight line, the speed is changing but the direction is not --> still, the object is accelerating

- For an object moving in a uniform circular motion, the speed is constant while the direction is changing --> still, the object is accelerating

So the correct answer is

a change in speed and/or direction

Learn more about acceleration:

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3 years ago

In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

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