<span>{<span>xi</span>,...}</span><span>|3|≥x</span>something like this
Hello here is a solution:
Answer:
Step-by-step explanation:
Solving for the variable , given that :
We can first start start by subtracting from both sides of the equation:
Now, we can divide both sides of the equation by the coefficient of , which would be :
Applying the fraction rule :
Then, apply the fraction rule
Answer: The minimum reliability for the second stage be 0.979.
Step-by-step explanation:
Since we have given that
Probability for the overall rocket reliable for a successful mission = 97%
Probability for the first stage = 99%
We need to find the minimum reliability for the second stage :
So, it becomes:
P(overall reliability) = P(first stage ) × P(second stage)
Hence, the minimum reliability for the second stage be 0.979.
Answer:b
Step-by-step explanation: