5 units, it’s the squares that go on that line
Answer:
11) x = 11
12) x = 11
Step-by-step explanation:
11) Δ RQP and Δ RLK are similar.
Hence, the ratios of the corresponding sides of the two triangles will be constant.
So, 
⇒ 
⇒ 
⇒ x - 4 = 7
⇒ x = 11 (Answer)
12) Δ QRS and Δ QDC are similar.
So, 
⇒ 
⇒ 2x - 14 = 8
⇒ 2x = 22
⇒ x = 11 (Answer)
Answer: q = 40
Step-by-step explanation:
Given the quadratic formula as
x = [-b +/-√(b^2 -4ac)]/2a
b = -14
a = 1
c = q
Difference d between the two roots.
d = [-b + √(b^2 -4ac)]/2a - [-b -√(b^2 -4ac)]/2a
d = 2√(b^2 -4ac)/2a
d = √(b^2 -4ac)/a
And d = 6
Substituting the values of a,b and c. We have;
6 = √[(-14^2) - (4×1×q)]
Square both sides
6^2 = 196 - 4q
4q = 196 - 36
q = 160/4
q = 40
The equation becomes
x^2 - 14x + 40 = 0
Answer:
15/10
Step-by-step explanation:
Since it is adding you need to get a common denominator(bottom number).
I know that 2 × 5 = 10 so now we multiply 3/5 × 2
we get 6/10
now the problem is 9/10 + 6/10
9 + 6 = 15 and the denominator is 10
15/10
