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3 years ago

What is the result of subtracting the second equation from the first? -4x-2y=-2 x-2y=9

Mathematics

1 answer:

diamong [38]3 years ago

6 0

Answer:

x=2.2

y=-3.4

Step-by-step explanation:

subtract the second from the first

-5x=-11

x=2=2

substituting by x in the first equation

so y=-3.4

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Solve absolute value of x-2=4

nika2105 [10]

Answer:

Step-by-step explanation:

2+4=6

you need to do the oppsite opporation and that the answer for example x-2=4 just add 2 and 4 and thats the answer that is aslo the same rule as divsion and multiplecation sorry for spelleng mistakes hope this helps!!!!!!

4 0

3 years ago

Read 2 more answers

The coordinates of point D are (7, 4) and the coordinates of point E are (1, −3) . What is the slope of the line that is perpend

Katarina [22]

The slope of a line is given by the change in y coordinates over the change in x coordinate.
The slope of line DE will be (4 - -3)/ (7-1) = 7/6
If M1 and M2 are slopes of two perpendicular lines at a point then
M1× M2 = -1
Thus, the slope of a perpendicular to line DE will be -6/7.

7 0

3 years ago

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction