Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
Answer: $10
Step-by-step explanation:
Given
Robin and his four friends bought tickets for 
each
If each one of them bought a calculator then the total spendings are 
Suppose the cost of each calculator is 
Cost per person is given by 
For the group, it is 
Equate this to total spendings
thus, the cost of each calculator is 
Answer:
C = 113.73 round it to the nearest tenth 114
9514 1404 393
Answer:
65 feet
Step-by-step explanation:
The problem involves finding the perimeter of a rectangle, then making adjustments to remove parts of the perimeter that aren't wanted.
The perimeter of a rectangle is given by the formula ...
P = 2(L+W)
For Aubrey's 12' × 8' room, the perimeter is ...
P = 2(12' +8') = 40'
This is the length of the border Aubrey needs at the ceiling.
__
At "waist-high", we need to subtract the total width of all the windows and doors. That total is ...
3' + 4' + 3' + 5' = 15'
So, the waist-high border is 40' -15' = 25'.
__
The total amount of border Aubrey needs is ...
ceiling border + waist-high border = 40' + 25' = 65'.
Aubrey needs 65 feet of border.
$17.60 is what she started out with. If she ended with $13.50, subtract the $4.70 so you get $8.80. Then you'd divide that by .5 to get 17.60.
