I NEED THIS ANSWER NOW! Determine which postulate or theorem can be used to prove that ABC DCB.

Mathematics

2 answers:

Archy [21]3 years ago

8 0

Quick Answer SSS
Proof
AC = DB
AB = DC
BC = BC This side is equal to itself and is common to both triangles.

Three sides of one triangle equal to 3 sides of the other means that the triangles are congruent. It is the Theorem you need.

Alla [95]3 years ago

7 0

Answer:

SSS

Step-by-step explanation:

You might be interested in

How u do ratios and divide because i have bad memories and its to many steps?

Drupady [299]

It depends on the question, but if the questions is sort of like "Person A and Person B shared 40 sweets in the ratio 3:5, how many sweets did Person A get" then you add 3 and 5 to get 8, and then you do 40 ÷ 8 to get 5 which is 1 in terms of the ratio. Then, you would multiply 5 by 3 to get 15 sweets. If it's a different type of question then let me know so I can help out :)

5 0

3 years ago

If your scale factor is 3/4, how will the scaled copy compare to the original?

Kisachek [45]

A scaled copy with the scale factor being 3/4 it would be smaller because it’s less than one so whenever there is a fraction that’s less than one then the shape would be smaller aswell

3 0

3 years ago

Javed saves Rs 50 000 in a bank. The annual interest is 2.5%. How much money will Mr Javed have in the account after one year? J

goldenfox [79]

Step-by-step explanation:

4 0

2 years ago

The angle of the semicircle is: a) 120 c) 180 b)60 d)90

AlexFokin [52]

Since there is no semicircle, the angle is 0.

8 0

3 years ago

Read 2 more answers

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

5 0

2 years ago