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Alexus [3.1K]
3 years ago
7

Use a calculator to determine the pattern of attractors for the equation y =kx(1-x) for the given value of k and the given initi

al value of x
K=3.26, x=0.8

Guys, I need help quickly?
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

0.5216

Step-by-step explanation:

Given the function  y =kx(1-x), the pattern of attractors are the value(s) of y at the initial value of k and x. Given the value of k = 3.26 and x = 0.8, to get the pattern of attractors, we will substitute the given initial value into the function as shown;

y =kx(1-x)\\\\y = 3.26(0.8)(1-0.8)\\\\y = 3.26*0.8*0.2\\\\y = 0.5216\\\\

Hence, the pattern of attractor for the equation y is 0.5216

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\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&&  y={{k }}x
\end{array}\\\\
-------------------------------\\\\

\bf \textit{we know that }\qquad 
\begin{cases}
y=42\\
x=6
\end{cases}\implies 42=k6\implies \cfrac{42}{6}=k
\\\\\\
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\\\\\\
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\\\\\\
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\\\\\\
\textit{what is "x" when y=28?}\qquad 28=7x\impliedby \textit{solve for "x"}
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