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3 years ago

If the rate 130 miles per 2 hours is reduced to a unit rate, the result is

Mathematics

1 answer:

sammy [17]3 years ago

3 0

Answer:

65 miles every 1 hour

Step-by-step explanation:

Unit rate is found once one of the units is 1. In this case we need to reduce the ratio so that it is 1 hour and we get a unit rate. We can do this by dividing both sided by 2 so that the hours are reduced to 1.

130=2

130/2=65 2/2=1

65=1

65 miles every hour

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Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough s

Xelga [282]

Answer:

Step-by-step explanation:

Complete Question:

Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?

a) n=600 p=0.2

b) n=20, p=0.4

if np=10 and npq=10 then the data follows normal distribution

a) np= 120,

q= 1-0.2= 0.8

npq= 600 ×0.2×0.4 = 48

Normal distribution is appropriate and sample size is large enough

b) np= 8

q= 1-0.4= 0.6

npq= 20 × 0.4×0.6= 4.8

sample size is not large enough so normal distribution is not appropriate.

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3 years ago

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3 years ago

Roland's Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 14 economy s

dmitriy555 [2]

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

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3 years ago