Question

The surface area covered by a rectangular playground is 200 yards. The width of the playground is twice as long as it's length. Using factors, find the length and the width of the playground

Answer 1

Answer:

The length is 10 yards and the width is 20 yards of the playground.

Step-by-step explanation:

Given,

Area of the rectangular playground = 200 yards.

Solution,

Let the length of the playground be x.

Then the width of the playground is 2x.

Now, According to the formula of area of rectangle;

$Area\ of\ rectangle =length\times width$

On substituting the values, we get;

$x\times 2x=200\\\\2x^2=200\\\\x^2=\frac{200}{2}=100\\\\x^2=100\\\\x=\sqrt{100}\\\\x=10\ yards$

So the length of the playground is 10 yards.

Since the width is twice of the length.

So width = $2x=2\times 10=20\ yards$

Hence the length is 10 yards and the width is 20 yards of the playground.