The sqrt of (34 m^4) is sqrt(34) times sqrt(m^4).
The sqrt of m^4 is easy ... that's just m^2 .
The other part is more messy. There's not much you can do with it.
sqrt(34) = sqrt(17) times sqrt(2).
That doesn't help make it any simpler.
You might as well just leave it as sqrt(34).
Then the final, simplified form of the original expression is
m^2 sqrt(34)
One half of 200 is 100 because 200 divided by 2 is 100
P.S: Please give me brainiest answer
Answer:
Step-by-step explanation:
we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e
- the area of the square equal to the area of the rectangle
therefore,
recall the formula of the area of square and rectangle so,
now assign variables
thus substitute:
simplify square:
divide both sides by 32:
and we're done!
Answer:
C
Step-by-step explanation:
This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.
Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:
10 C 6 = 10!(6!4!)
If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1
10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]
10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]
We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3
10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]
We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:
10 C 6 = 10*3*7*/1 = 210/1= 210
So, option C
