Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
B inventory
Add purchase
Add fright inward
Total amount to be account for
Less E inventory
11.2 you could do 112/10 or 22.4/2.
The answers
1)-7
2)-1.5
3) 2
80
Step-by-step explanation:
5×6 = 30 and 30×8 = 240 divide that by three you get 80
