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irakobra [83]
3 years ago
15

A random sample of 100 students was taken. Of the 100 students, 50 liked vanilla ice cream, 37 liked chocolate ice cream, and 13

liked strawberry ice cream. If the student population is 1200, how many students like chocolate ice cream?
A. 444
B. 600
C. 37
D. 156​
Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

444

Step-by-step explanation:

since 37/100 students liked chocolate you need to scale that data to the new data size and find thirty seven percent of 1200 which is 444

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Tyrone and Terri both bought sofas with installment loans. Tyrone bought a sofa with a
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Answer:

Tyrone paid the higher markup rate.

Step-by-step explanation:

Tyrone and Terri both bought sofas with installment loans.

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Terri bought his own with sticker price of $950 by paying $52 a month for 24 months. Therefore,

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6 0
3 years ago
4th term of an arithmetic sequence is 23 and its 11th term is 65, what is its common difference​
Rudik [331]

Answer:

d = 6

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₄ = 23 and a₁₁ = 65 , then

a₁ + 3d = 23 → (1)

a₁ + 10d = 65 → (2)

Subtract (1) from (2) term by term to eliminate a₁

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5 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
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The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

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