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Alexeev081 [22]
3 years ago
14

Simply the expression below (10-3i)(2-5i)

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

7i and 3i

hope this helps <33

rewona [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Use foil method

(10 - 3i) (2 -5i) = 10*2 + 10*(-5i)  +  (-3i)*2 + (-3i)*(-5i)

   = 20 - 50i -6i + 15i²

   = 20 - 50i - 6i + 15*(-1)             {i² = -1}

   = 20  - 50i - 6i - 15

   = 20 - 15 - 50i - 6i

   = 5 - 56i

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Price p of a ice cream is $3.95 plus $0.85 for each topping t on ice cream
Talja [164]
I don't know if you are asking for an equation but if you are, here ya go.

P = $3.95 + $0.85t
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3 years ago
Factorise 2x^2 - 3x -2 &lt; 0
Galina-37 [17]
Step 1: Factor 2 x^{2} - 3x -2
1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite -3x as the sum of x and -4x

2 x^{2} +x-4x-2\ \textless \ 0


Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.

</span>x(2x+1)-2(2x+1)\ \textless \ 0
<span>
Step 3: </span>Factor out the common term 2x+1

(2x+1)(x-2)\ \textless \ 0

Step 4: Solve for x

1. Ask: When will (2x+1)(x-2) equal zero?
2. Answer: When 2x + 1 = 0 or x-2=0
3. <span>Solve each of the 2 equations above:

</span>x=- \frac{1}{2} ,2
<span>
Step 5: </span>From the values of x <span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: P</span><span>ick a test point for each interval

</span>For the interval x\ \textless \ - \frac{1}{2} &#10;
Lets pick x=-1. Then, 2(-1) ^{2} -3 * -1 -2 \ \textless \  0
After simplifying, we get 3\ \textless \ 0, Which is false. 
Drop this interval.
<span>
For this interval - \frac{1}{2} \ \textless \ x\ \textless \ 2
Lets pick x=0. Then, 2* 0^{2} - 3 * 0-2\ \textless \ 0. After simplifying, we get -2\ \textless \ 0, which is true. Keep this <span>interval.

For the interval </span>x\ \textgreater \ 2

Lets pick x = 3. Then, 2 * 3  ^{2} -3*3-2\ \textless \ 0. After simplifying, we get 7\ \textless \ 0, Which is false. Drop this interval.

.Step 7: Therefore, 
- \frac{1}{2} \ \textless \ x\ \textless \ 2

Done! :)</span>
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Evaluate the expression 5×5^2÷5-6
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Step-by-step explanation:

according to BODMAS

5×5^2÷5-6

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a trapezoide has an area of 150 square meters. If the bases are 14 meters and 16 meters, what is the height of the trapezoid​
SIZIF [17.4K]

Answer:

h = 10 m

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The formula for area of a trapezoid is  

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150 = (1/2)(16 + 14)(h)

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