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PSYCHO15rus [73]
3 years ago
15

Calculate the volume of a cylinder of height 7 cm and radius 4 cm (take π)​

Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:

351.68

Step-by-step explanation:

v=\pir^2h

v= 3.14(4)^2(7)

v= 3.14(16)7

v= 3.14 times 112

v=351.68

hope this helps

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Find the equation of the exponential function represented by the table below:
IgorC [24]

Answer:

y=2^{1-x}

Step-by-step explanation:

<u>Exponential Function</u>

When we need to express the exponential relation between two variables, we use the equation

y=Cr^{x}

where C, r are constants to be determined by using the given points from the table

For x=0, y=2, thus

2=C.r^{0}=C

We find that C=2

The equation is now

y=2r^{x}

Now we use the point x=1, y=1

1=2r

We find that

\displaystyle r=\frac{1}{2}

Thus, the equation is

\displaystyle y=2\left(\frac{1}{2}\right)^{x}

Rearranging

y=2(2)^{-x}=2^{1-x}

The required equation is

y=2^{1-x}

We can easily verify the last two points are also obtained by using the equation

7 0
3 years ago
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3 0
2 years ago
Find the difference between 3 more than 1/3 and 3.
AveGali [126]

Answer:

1/3

Step-by-step explanation:

6 0
3 years ago
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What value of c is needed to complete the square?<br><br> X2 + 10x + c = -3+ c
Vikentia [17]

Answer:

Step-by-step explanation:Let's solve for c.

x2+10x+c=−3+c

Step 1: Add -c to both sides.

x2+c+10x+−c=c−3+−c

x2+10x=−3

Step 2: Add -x^2 to both sides.

x2+10x+−x2=−3+−x2

10x=−x2−3

Step 3: Add -10x to both sides.

10x+−10x=−x2−3+−10x

0=−x2−10x−3

Step 4: Divide both sides by 0.

0

0

=

−x2−10x−3

0

c=

−x2−10x−3

0

Answer:

c=

−x2−10x−3/0

hope it helps :D

4 0
3 years ago
Tan^2theta - Sin^2theta = tan^2theta. sin^2theta <br> explain this step<br>​
denis23 [38]

tan²(<em>θ</em>) - sin²(<em>θ</em>) = sin²(<em>θ</em>)/cos²(<em>θ</em>) - sin²(<em>θ</em>)

-- because tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>) by definition of tangent --

… = sin²(<em>θ</em>) (1/cos²(<em>θ</em>) - 1)

-- we pull out the common factor of sin²(<em>θ</em>) from both terms --

… = sin²(<em>θ</em>) (1/cos²(<em>θ</em>) - cos²(<em>θ</em>)/cos²(<em>θ</em>))

-- because <em>x</em>/<em>x</em> = 1 (so long as <em>x</em> ≠ 0) --

… = sin²(<em>θ</em>) ((1 - cos²(<em>θ</em>))/cos²(<em>θ</em>))

-- we simply combine the fractions, which we can do because of the common denominator of cos²(<em>θ</em>) --

… = sin²(<em>θ</em>) (sin²(<em>θ</em>)/cos²(<em>θ</em>))

-- due to the Pythagorean identity, sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1 --

… = sin²(<em>θ</em>) tan²(<em>θ</em>)

-- again, by definition of tan(<em>θ</em>) --

8 0
3 years ago
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