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sertanlavr [38]

3 years ago

6

find the mean, median, and mode of the data set round to the nearest tenth 15, 1 , 4, 4, 8, 7, 15, 4, 5

2 answers:

Dmitriy789 [7]3 years ago

6 0

$15,\ 1,\ 4,\ 4,\ 8,\ 7,\ 15,\ 4,\ 15,\ 4,\ 5\to\underbrace{1,\ 4,\ 4,\ 4,\ 4,\ 5,\ 7,\ 8,\ 15,\ 15,\ 15}_{11}\\\\mean=\dfrac{1+4+4+4+4+5+7+8+15+15+15}{11}=\dfrac{82}{11}\approx7.5\\\\median:1,\ 4,\ 4,\ 4,\ 4,\ \boxed{5},\ 7,\ 8,\ 15,\ 15,\ 15\\\\mode:1,\ \underbrace{4,\ 4,\ 4,\ 4}_{4},\ 5,\ 7,\ 8,\ 15,\ 15,\ 15$

<h3>Answer: mean = 7.5, median = 5, mode = 4</h3>

Dafna11 [192]3 years ago

4 0

Answer:

Mean = 7.5, median = 5, mode = 4

Step-by-step explanation:

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If the 7th of an AP is equal to 11 times the 11th term, find the 18th term

Zina [86]

Answer:

-33 or 33

Step-by-step explanation:

The seventh term of an AP is written as:

$a + 6d$

The eleventh term of an AP is written as:

$a + 10d$

If the 7th term is 11 times the 11th term, then;

$a + 6d = 11(a + 10d)$

Expand to get:

$a + 6d = 11a + 110d$

$11a - a = 6d - 110d$

$10a = - 104d$

$\frac{a}{d} = - \frac{104}{10}$

$\frac{a}{d} = - \frac{52}{5}$

We must have a=-52 and d=5

Or

a=52 and d=-5

For the first case, the 18th term is :

$- 52 + 5 \times 17 = 33$

For the second case,

$52 - 5 \times17 = - 33$

3 0

3 years ago

16x^0+2x^2*y^-1 x=2 y=4<br> PLEASE HELP!!!

Kipish [7]

Answer:

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3 0

3 years ago

Write the ratio for sin A and cos A. The triangle is not drawn to scale.

Zolol [24]

Option A:

$$ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Solution:

Given data:

AB = 50, BC = 48, AC = 14

To find the value of sin A and cos A:

$$\sin A= \frac{Opposite \ side}{Hypotenuse}$

$$\sin A= \frac{AC}{AB}$

$$\sin A= \frac{14}{50}$

$$\cos A= \frac{Adjacent \ side}{Hypotenuse}$

$$\cos A= \frac{BC}{AB}$

$$\cos A= \frac{48}{50}$

$$\therefore \ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Hence option A is the correct answer.

7 0

3 years ago

Is (x+1)^2 equivalent to x^2 + 1? explain

Mademuasel [1]

Answer:

No.

Step-by-step explanation:

(x+1)^2=(x+1)(x+1)=x^2+x+x+1=x^2+2x+1

This is different from x^2+1.

Thus, they are not equivalent.

4 0

2 years ago

Evaluate x-2 for x = -3.

Katen [24]

I think the answer is -3-2= -5

5 0

3 years ago