Find the mean and mode of the set of data. 8, 7, 4, 6, 6

natita [175]

Hey!

To solve this equation, we'd first have to apply the distributing rule to this equation.

Original Equation :
$( 3a - 2 )^{2}$

New Equation {Changed by Applying the Distribution Rule} :
$( 3a )^{2} - 2$ · 3a · 2 + $2 ^{2}$

And now we simplify.

Old Equation :
$( 3a ) ^{2} -2$ · 3a · 2 + $2 ^{2}$

New Equation {Old Equation Simplified} :
$9a ^{2}$ - 12a + 4

So, the equation $(3a - 2) ^{2}$ simplified is $9a ^{2}$ - 12a + 4.

Hope this helps!

- Lindsey Frazier ♥

5 0

3 years ago

The set of types of matter well difined or not

Tresset [83]

Answer:

It is not well defined.

Step-by-step explanation:

Because set is a collection of well defined objet. And matter contains of solid, liquid and gas

3 0

3 years ago

What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34 Round yo

Galina-37 [17]

We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.

The probability of a data score between two z-scores is given by formula $P(a$ .

Using above formula, we will get:

$P(-1.32$

Now we will use normal distribution table to find probability corresponding to both z-scores as:

$P(-1.32$

Now we will convert $0.27351$ into percentage as:

$0.27351\times 100\%=27.351\%$

Upon rounding to nearest tenth of percent, we will get:

$27.351\%\approx 27.4\%$

Therefore, our required probability is 27.4% and option C is the correct choice.

5 0

3 years ago

What would the radius of a circle be with a diameter of 24?

Montano1993 [528]

Answer:

r = 12

Step-by-step explanation:

using the formula

d = 2 r

solving for r

r = d/2= 24/2=12

8 0

3 years ago

Read 2 more answers

John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo

yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

$\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6$

3 0

2 years ago