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3 years ago

2=(-3)+5x Solve for x

Mathematics

2 answers:

slega [8]3 years ago

5 0

Answer: x=1

Step-by-step explanation: I don't know how to explain it.

Alja [10]3 years ago

4 0

Answer:

x = 1

Step-by-step explanation:

First, add 3 to both sides to isolate the variable. This leaves us with the following:

5 = 5x

Now, divide both sides by 5. This leaves us with our answer:

x = 1

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Amelia randomly selects two cards, with replacement, from a normal deck of cards. Calculate the probability that: the first card

Lena [83]

Answer:

1 / 2704

Step-by-step explanation:

Number of cards in a deck = 52

9 of clubs in a deck = 1

10 of clubs in a deck = 1

Probability = required outcome / Total possible outcomes

P(9 of club) = 1 / 52

With replacement ;

Then ;

P(10 of club) = 1 / 52

Hence,

P(9 of club, then 10 of club) = 1/52 * 1/52 = 1 / 2704

3 0

3 years ago

Which of the following is a correct interpretation of the expression 2 + 72+72, plus, 7?

Soloha48 [4]

Answer:

Im not sure but im pretty sure it is 9+144

Step-by-step explanation:

3 0

3 years ago

The simplest form of 4√576 is ?

N76 [4]

Answer:

96 or √144

Step-by-step explanation:

Divide 576 by 4 to get 144. There will be no values outside of the square root sign because 4 goes directly into 576 with no remainders.

8 0

3 years ago

Read 2 more answers

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

9 cm

lions [1.4K]

Answer:

I think it's 149cm

Step-by-step explanation:

I just doubled the numbers and multiplied them

7 0

3 years ago