Question

one town, 64% of adults have health insurance. What is the probability that 10 adults selected at random from the town all have health insurance?

Answer 1

Answer:

The probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

Step-by-step explanation:

Consider the provided information.

One town, 64% of adults have health insurance.

Let p = 64% = 0.64

Therefore, q=1-0.64=0.36

We need to find the probability that 10 adults selected at random from the town all have health insurance

Use the formula: $P(x)=^nC_r(p)^r(q)^{n-r}$

Here, the value of r is 10.

Substitute the respective values in the above formula.

$P(x)=^{10}C_{10}(0.64)^{10}(0.36)^{10-10}$

$P(x)=(0.64)^{10}(0.36)^{0}\\P(x)=(0.64)^{10}\\P(x)\approx0.01153$

Hence, the probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.